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klio [65]
3 years ago
9

What is the polynomial function of lowest degree with lead coefficient 1 and roots 1 and 1 + i?

Mathematics
2 answers:
Helga [31]3 years ago
5 0

Answer:

f(x) = x3 – 3x2 + 4x – 2

Step-by-step explanation:

astra-53 [7]3 years ago
4 0

x³ - 3x² + 4x - 2

complex roots occur in conjugate pairs

1 + i is a root then so is 1 - i

the factors of the polynomial are therefore

f(x) = (x - 1 )(x - (1 + i))(x - (1 - i))

     = (x - 1 )(x² - 2x + 2 ) ( expand factors and simplify )

     = x³ - 3x² + 4x - 2



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−2/3(3x−4)+3x=5/6 whoever gets right gets brainlyest
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−2/3(3x−4)+3x=5/6

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[[((3^3 - 7) • 5)/10] + ((1 + 3 + 6 + 9) - 10)]
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Step-by-step explanation:

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7 0
3 years ago
When using the rational root theorem, which of the following is a possible root of the polynomial function below f(x)=x^3-5x^2-1
uranmaximum [27]

Answer:

\Large \boxed{\sf \ \ 7 \ \ }

Step-by-step explanation:

Hello, please consider the following.

The polynomial function is

x^3-5x^2-12x+14

The rational root theorem states that each rational solution

   x=\dfrac{p}{q}    

, written in irreducible fraction, satisfies the two following:

   p is a factor of the constant term

   q is a factor of the leading coefficient

In this example, the constant term is 14 and the leading coefficient is 1. It means that p is a factor of 14 and q a factor of 1.

Let's proceed with the prime factorisation of 14:

14 = 2 * 7

Finally, the possible rational roots of this expression are :

   1

   2

   7

   14

and we need to test for negative ones too

   -1

   -2

   -7

   -14

From your list, the correct answer is 7.

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

7 0
4 years ago
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