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MAVERICK [17]
4 years ago
11

Solve

+3x - 9 = 0" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
MArishka [77]4 years ago
3 0

Answer:

x= \frac{3-3\sqrt{7}i }{4} and x= \frac{3+3\sqrt{7}i }{4}

Step-by-step explanation:

We have to solve the given equation - 2x² + 3x - 9 = 0

To solve the equation given above we have to factorize the left-hand side of the equation.

But it can not be factorized. So, use the Sridhar Achaya formula.

Therefore, x= \frac{-3 + \sqrt{3^{2}-4 \times (-2) \times (-9) } }{2\times (-2)} and x= \frac{-3 -\sqrt{3^{2}-4 \times (-2) \times (-9) } }{2\times (-2)}

So,  x= \frac{3-3\sqrt{7}i }{4} and x= \frac{3+3\sqrt{7}i }{4} {Where i=\sqrt{-1}}

Therefore, the solutions are imaginary numbers. (Answer)

Note: The Sridhar Acharya Formula gives if ax² + bx + c = 0, then the roots of the equation are x = \frac{-b + \sqrt{b^{2}-4ac } }{2a} and x = \frac{-b - \sqrt{b^{2}-4ac } }{2a}.  

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