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emmainna [20.7K]
3 years ago
6

PLZ HELP WILL RATE BRAINLIEST REMEMBER IT HAS 5 DIGITS

Mathematics
2 answers:
kobusy [5.1K]3 years ago
7 0

Answer:

i figured it out the number is 12,316 if i am correct

Kruka [31]3 years ago
4 0

Answer:

<em>The number: 13,226</em>

Step-by-step explanation:

1. The smallest 5-digit number possibile is: 10,000

2. The smallest 5-digit number being odd should be: 10,001

3. All factors of 6 are {1, 2, 3, 6} so that the smallest possible way to arrange these numbers would be: 11,236

4.  Now this number contains 3 prime numbers, 2 being {2 and 3}. If we were to consider another prime number, still being a factor of 6, that would be: 2. That would mean instead of the 1 being the second digit of the value 11,236 it could be 2: 12,236.

5. The digit in the thousands place (2) should be greater than the digit in the tens place (3). Let's swap these digits for now so that condition is satisfied: 13,226. 2 is the only number that has a number greater than it, besides 1, but 1 can't be a digit in the tenth place as it would make a greater 5 digit-number. Thus, p<em>rovided the conditions are still satisfied, the number 13,226 is the smallest number possible</em>.

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Let P(x) be the statement"x= x2", If the domain consists of the integers, what are these truth values? (a) P(0) (b) P(1) (c) P(2
jeka57 [31]

Answer: i guess the problem is with P(x) => "x = x^{2}", then P(x) is true if that equality is true, and is false if the equality is false.

so lets see case for case.

a) x = 0, and 0^{2} = 0. So p(0) is true.

b) x = 1 and 1^{2} = 1, so P(1) is true.

c) x = 2, and 2^{2} = 4, and 2 ≠ 4, then P(2) is false.

d) x= -1 and 1^{2} = 1, and 1 ≠ -1, so P(-1) is false.

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Answer: S<\-2

Hope i was some help.

Step-by-step explanation: sorry I can’t put the right sign my keybored won’t let me but you know what it stands for.

3s+6s</-5(s+2)

start off with -5(s+2) you multiply -5 with s and it is -5s then you do the same for +2 take -5 and multiply by +2 pos times a neg is always a neg so it’s -10.

3s+6<\-5s-10

So you have to get rid of the -5s so your going to do the inverse which is add 5 to -5 and it will get rid of -5s but then you have to add 5 to 3s and that will be 8s.

8s+6</-10

Now your going to get rid of the +6 and to do that you do the inverse you subtract 6 and it will get rid of it now you have to do the same for -10 so you will subtract 6 to -10 and that will equal -16.

Now you have to divide!

8s/8 </ -16/8

And it should equal s <\-2

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3 years ago
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