Answer:
<em>The number: 13,226</em>
Step-by-step explanation:
1. The smallest 5-digit number possibile is: 10,000
2. The smallest 5-digit number being odd should be: 10,001
3. All factors of 6 are {1, 2, 3, 6} so that the smallest possible way to arrange these numbers would be: 11,236
4. Now this number contains 3 prime numbers, 2 being {2 and 3}. If we were to consider another prime number, still being a factor of 6, that would be: 2. That would mean instead of the 1 being the second digit of the value 11,236 it could be 2: 12,236.
5. The digit in the thousands place (2) should be greater than the digit in the tens place (3). Let's swap these digits for now so that condition is satisfied: 13,226. 2 is the only number that has a number greater than it, besides 1, but 1 can't be a digit in the tenth place as it would make a greater 5 digit-number. Thus, p<em>rovided the conditions are still satisfied, the number 13,226 is the smallest number possible</em>.
