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LenaWriter [7]
3 years ago
15

Solve for y. -80 + y = 80 y=0 y=-160 y = 160

Mathematics
1 answer:
Galina-37 [17]3 years ago
5 0

Answer:y = 160

Step-by-step explanation:

The given equation is expressed as

-80 + y = 80

It is a linear equation with only one variable. The variable is y. The constants on the left hand side of the equation and the right hand side of the equation are - 80 and 80 respectively. To determine the value of the variable, y, we would eliminate the constant on the left hand side of the equation by adding 80 to the left hand side of the equation and the right hand side of the equation. It becomes

-80 + 80 + y = 80 + 80

0 + y = 160

y = 160

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A clerk is marking up merchandise 34%. The original price of an item is $455. What will be the retail price?
Galina-37 [17]
Take the orginal price and multiply it by 1.34.
455 * 1.34 = $609.70 in retail.

The longer way would be to take 34% of 455 and then add it to 455.

4 0
3 years ago
The question is in the photo.
netineya [11]

Answer:

1

0.8

0.4

Step-by-step explanation:

y = 5x

Substituting '5':

5 = 5x

x = 5/5

x = 1

Substituting 4:

4 = 5x

x = 4/5

x = 0.8

Substituting 2:

2 = 5x

x = 2/5

x = 0.4

5 0
2 years ago
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What is the remainder when 9712 is divided by 42
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9712/42=231.238 should be your answer
6 0
3 years ago
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Please help me! i'll mark you brainliest <br> 20 points, (maths)
marysya [2.9K]

Answer:

5/6 of the time or 50 minutes

Step-by-step explanation:

6 0
3 years ago
I need answer on this graphing va substitution.Problem 7 I tried to solve it but not sure that’s correct
Bond [772]

Given the system of equations:

\begin{gathered} 2x+9y=27 \\ x-3y=-24 \end{gathered}

To solve it by substitution, follow the steps below.

Step 1: Solve one linear equation for x in terms of y.

Let's choose the second equation. To solve it for x, add 3y to each side of the equations.

\begin{gathered} x-3y=-24 \\ x-3y+3y=-24+3y \\ x=-24+3y \end{gathered}

Step 2: Substitute the expression found for x in the first equation.

\begin{gathered} 2x+9y=27 \\ 2\cdot(-24+3y)+9y=27 \\ -48+6y+9y=27 \\ -48+15y=27 \end{gathered}

Step 3: Isolate y in the equation found in step 2.

To do it, first, add 48 to both sides.

\begin{gathered} -48+15y=27 \\ -48+15y+48=27+48 \\ 15y=75 \end{gathered}

Then, divide both sides by 15.

\begin{gathered} \frac{15y}{15}=\frac{75}{15} \\ y=5 \end{gathered}

Step 4: Substitute y by 5 in the relation found in step 1 to find x.

\begin{gathered} x=-24+3y \\ x=-24+3\cdot5 \\ x=-24+15 \\ x=-9 \end{gathered}

Answer:

x = -9

y = 5

or (-9, 5)

Also, you can graph the lines by choosing two points from each equation, according to the picture below.

7 0
1 year ago
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