4 years ago

I will give brainliest if right!!!!!

Mathematics

1 answer:

kotegsom [21]4 years ago

8 0

The second graph where the intersection is in the first quadrant

You might be interested in

What is 20÷1÷[(10÷5)÷2]

marysya [2.9K]

Answer: 20

Step-by-step explanation:

Follow order of operations (PEMDAS)

20÷1÷[(10÷5)÷2] Given

20÷1÷[(2)÷2] Do 10÷5 in parenthesis

20÷1÷[(1)] Do (2)÷2

20÷1 Do 1÷[(1)]

20 Do 20÷1, and that is your answer

8 0

4 years ago

What is the equation of this graphed line?

koban [17]

Answer:

Haven't done this in a minute but I think it's (2,1)

6 0

3 years ago

Read 2 more answers

What is 825x92. (just practice for 25 points)

Leno4ka [110]

75900 is your answer.

6 0

3 years ago

Read 2 more answers

Please help ♡♡♡♡♡♡♡

lions [1.4K]

Step-by-step explanation:

$\angle AOB$ and $\angle BOC$ are linear pair angles.

$\therefore m\angle AOB + m\angle BOC = 180° \\ \therefore \: 3x + 124 \degree + 6x + 29 \degree = 180° \\ \therefore \: 9x + 153 \degree = 180° \\ \therefore \: 9x = 180° - 153 \degree \\ \therefore \: 9x = 27 \degree \\ \therefore \:x = \frac{27 \degree }{9} \\ \huge \pink{ \boxed{\therefore \:x =3 \degree }} \\ \\ \because \: m\angle BOC =6x + 29 \degree \\ \therefore \: m\angle BOC =6 \times3 \degree + 29 \degree \\ \therefore \: m\angle BOC = 18\degree + 29 \degree \\ \\ \huge \red{ \boxed{\therefore \: m\angle BOC = 47 \degree }}$

5 0

4 years ago

In discus competition an athlete threw the discus 63.37meters 62.95 meters and 63.7meters order the distance from least to great

Eduardwww [97]

62.95meters, 63.37meters, 63.7meters.

6 0

3 years ago

Read 2 more answers