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Shalnov [3]
3 years ago
10

richard bought rolls for a bbq he bought 4 1/4 dozen wheat rolls and 5 2/3 snowflake rolls if 4 1/3 were eaten at the bbq how ma

ny dozen rolls does richard have left
Mathematics
2 answers:
Diano4ka-milaya [45]3 years ago
7 0

Answer: Richard has 5 7/12 rolls left.

Step-by-step explanation:

Hi to answer this question, first, we have to sum the amount of rolls Richard bought for the bbq:

4 1/4 + 5 2/3 = 4 3/12 + 5 8/12 = 9 11/12

Finally we have to subtract the amount of rolls eaten at the bbq to the previous number.

9 11/12 - 4 1/3 = 9 11/12 - 4 4/12= 5 7/12  

So, Richard has 5 7/12 rolls left.

Feel free to ask for more if needed or if you did not understand something.

victus00 [196]3 years ago
4 0
The equation for this would be 41/4 + 52/3 - 41/3= ?
So then you just change all the denominators to their lcm, which is 12 and multiply the numerator accordingly.
123/12 + 208/12 - 164/12 = 167/12
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What would be the coordinates of triangle A'B'C' if triangle ABC was dilated by a factor of
notsponge [240]

Answer:

A(0,0)\rightarrow A'(0,0) \\ B(2,0)\rightarrow B'(\frac{2}{3},0) \\ C(0,2)\rightarrow C'(0,\frac{2}{3})

Step-by-step explanation:

The question is as following:

The verticies of a triangle on the coordinate plane are

A(0, 0), B(2, 0) and C(0, 2).

What would be the coordinates of triangle A'B'C' if triangle ABC was dilated by a factor of 1/3 ?

=============================================

Given: the vertices of a triangle ABC are A(0, 0), B(2, 0) and C(0, 2).

IF the triangle is dilated by a factor of k about the origin, then

(x,y) → (kx , ky)

that triangle ABC was dilated by a factor of 1/3 to create the triangle A'B'C'.

It is given that triangle ABC was dilated by a factor of 1/3 to create the triangle A'B'C'.

If a figure dilated by a factor of 1/3 about the origin

So, (x,y)\rightarrow (\frac{1}{3}x,\frac{1}{3}y)

<u>So, The coordinates of the triangle A'B'C' are:</u>

A(0,0)\rightarrow A'(0,0) \\ B(2,0)\rightarrow B'(\frac{2}{3},0) \\ C(0,2)\rightarrow C'(0,\frac{2}{3})

6 0
3 years ago
What is the distance (in units) between points C and D? Round your answer to the nearest hundredth.
r-ruslan [8.4K]

Given:

The two points on a coordinate plane are C(-5,-1) and D(0,3).

To find:

The distance between C and D.

Solution:

Distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Using the distance formula, the distance between C(-5,-1) and D(0,3) is

CD=\sqrt{(0-(-5))^2+(3-(-1))^2}

CD=\sqrt{(0+5)^2+(3+1)^2}

CD=\sqrt{(5)^2+(4)^2}

CD=\sqrt{25+16}

On further simplification, we get

CD=\sqrt{41}

CD=6.40312424

CD\approx 6.40

Therefore, the distance between C and D is 6.40 units.

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Answer:

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