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adelina 88 [10]
2 years ago
6

The temperature of a freezer started at 18 degrees Celsius.After cooling for a few hours, the freezer had a temperature of -12 d

egrees Celsius. What is the difference between the new,colder temperature and the original temperature?
Mathematics
1 answer:
bixtya [17]2 years ago
4 0

Answer:

Step-by-step explanation:

Difference = New temperature - original temperature

                  = -12 - (18)

                 = - 30

New temperature is 30° less than the original temperature

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Evaluate each of the expressions in the list for y = 5. Drag and drop the correct number into each box to
malfutka [58]

Answer:

Step-by-step explanation:

To get the value of the expressions in list A and list B we will substitute y = 5 in each expression.                      

            List A                                        List B

1). 6 + 6y = 6 + 6(5) = 36              6y - 6 = 6(5) - 6 = 24

2). 6(y - 1) = 6(5 - 1) = 24               6(y + 1) = 6(5 + 1) = 36

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2 years ago
∜64= 4ˣ, what is the value of x?
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Answer:

x = (2 i π n)/log(4) + log(2 sqrt(2))/log(4) for n element Z

Step-by-step explanation:

Solve for x:

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Hint: | Reverse the equality in 2 sqrt(2) = 4^x in order to isolate x to the left hand side.

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Take the logarithm base 4 of both sides:

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