All categories

2 years ago

Evaluate the expression for the given values. (12x+5y)/3z, where x = 12, y = 6, and z = 4. (write answer in decimal form)

Mathematics

1 answer:

Pachacha [2.7K]2 years ago

5 0

Answer:

14.5

Step-by-step explanation:

12×12=144 5×6=30 144+30=174 3×4=12 174/12=14.5

You might be interested in

What is the answer to 2x=24

Digiron [165]

Answer:

Step-by-step explanation:

you divide 24 by 2 because it is multiplication, and the opposite is division.

5 0

2 years ago

Read 2 more answers

Mary purchased a prepald phone card for $30. Long distance calls cost 8 cents a minute using this card. Mary used her card only

julia-pushkina [17]

Hey can I have brainlyist I only need one more :)

4 0

2 years ago

Which are the solutions of x2 = 19x + 1?

Finger [1]

Answer:

$(\frac{19-\sqrt{365}} {2},\frac{19+\sqrt{365}} {2})$

Step-by-step explanation:

we have

$x^2=19x+1$

we know that

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-x^{2}-19x-1=0$

$a=1\\b=-19\\c=-1$

substitute in the formula

$x=\frac{-(-19)\pm\sqrt{-19^{2}-4(1)(-1)}} {2(1)}$

$x=\frac{19\pm\sqrt{365}} {2}$

$x=\frac{19+\sqrt{365}} {2}$

$x=\frac{19-\sqrt{365}} {2}$

$(\frac{19-\sqrt{365}} {2},\frac{19+\sqrt{365}} {2})$

therefore

StartFraction 19 minus StartRoot 365 EndRoot Over 2 EndFraction comma StartFraction 19 + StartRoot 365 EndRoot Over 2 EndFraction

6 0

3 years ago

Read 2 more answers

Can someone explain what geometric sequences are?

Fed [463]

Explanation:

A sequence is a list of numbers.

A geometric sequence is a list of numbers such that the ratio of each number to the one before it is the same. The common ratio can be any non-zero value.

Examples

1, 2, 4, 8, ... common ratio is 2
27, 9, 3, 1, ... common ratio is 1/3
6, -24, 96, -384, ... common ratio is -4

___

General Term

Terms of a sequence are numbered starting with 1. We sometimes use the symbol a(n) or an to refer to the n-th term. The general term of a geometric sequence, a(n), can be described by the formula ...

a(n) = a(1)×r^(n-1) . . . . . n-th term of a geometric sequence

where a(1) is the first term, and r is the common ratio. The above example sequences have the formulas ...

a(n) = 2^(n -1)
a(n) = 27×(1/3)^(n -1)
a(n) = 6×(-4)^(n -1)

You can see that these formulas are exponential in nature.

Sum of Terms

Another useful formula for geometric sequences is the formula for the sum of n terms.

S(n) = a(1)×(r^n -1)/(r -1) . . . . . sum of n terms of a geometric sequence

When |r| < 1, the sum converges as n approaches infinity. The infinite sum is ...

S = a(1)/(1-r)

8 0

3 years ago

suppose that you borrow $12000 for 4 years at 6% towards the purchase of a car. use pmt to find the monthly payments and the tot

son4ous [18]

Answer:

Equivalent representations of percent problems

Step-by-step explanation:

3 0

2 years ago