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3 years ago

5

hey so i'm in 8th grade and am excelled in math... i'm in 10th grade math(geometry) and my teacher gave us a desmos activity (ki

nda like a pretest) and well there was this one question to find "X" and well i tend to over complicate things and did that here. in the picture you will see in the bottom right that i place 2 30 degree angles and assumed that it was split in half by the middle line, well my teacher saw that and told me that my answer was right, but he wanted to know how i did it, he saw i assumed those angles and kept on looking at it, well basically my question is "is there a principle describing that this is right? or some equation/method?"

1 answer:

stich3 [128]3 years ago

3 0

Answer:

80 degrees.

Step-by-step explanation:

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The top and bottom margins of a poster are each 15 cm and the side margins are each 10 cm. If the area of printed material on th

12345 [234]

Answer:

the dimension of the poster = 90 cm length and 60 cm width i.e 90 cm by 60 cm.

Step-by-step explanation:

From the given question.

Let p be the length of the of the printed material

Let q be the width of the of the printed material

Therefore pq = 2400 cm ²

q = $\dfrac{2400 \ cm^2}{p}$

To find the dimensions of the poster; we have:

the length of the poster to be p+30 and the width to be $\dfrac{2400 \ cm^2}{p} + 20$

The area of the printed material can now be: $A = (p+30)(\dfrac{2400 }{p} + 20)$

= $2400 +20 p +\dfrac{72000}{p}+600$

Let differentiate with respect to p; we have

$\dfrac{dA}{dp}= 20 - \dfrac{72000}{p^3}$

Also;

$\dfrac{d^2A}{dp^2}= \dfrac{144000}{p^3}$

For the smallest area $\dfrac{dA}{dp }=0$

$20 - \dfrac{72000}{p^2}=0$

$p^2 = \dfrac{72000}{20}$

p² = 3600

p =√3600

p = 60

Since p = 60 ; replace p = 60 in the expression q = $\dfrac{2400 \ cm^2}{p}$ to solve for q;

q = $\dfrac{2400 \ cm^2}{p}$

q = $\dfrac{2400 \ cm^2}{60}$

q = 40

Thus; the printed material has the length of 60 cm and the width of 40cm

the length of the poster = p+30 = 60 +30 = 90 cm

the width of the poster = $\dfrac{2400 \ cm^2}{p} + 20$ = $\dfrac{2400 \ cm^2}{60} + 20$ = 40 + 20 = 60

Hence; the dimension of the poster = 90 cm length and 60 cm width i.e 90 cm by 60 cm.

4 0

3 years ago

Please help me find the area of shaded region and step by step

Bumek [7]

Answer:

Part 1) $A=60\ ft^2$

Part 2) $A=80\ cm^2$

Part 3) $A=96\ m^2$

Part 4) $A=144\ cm^2$

Part 5) $A=9\ m^2$

Part 6) $A=(49\pi -33)\ in^2$

Step-by-step explanation:

Part 1) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior rectangle

The area of rectangle is equal to

$A=bh$

where

b is the base of rectangle

h is the height of rectangle

so

$A=(12)(7)-(8)(3)$

$A=84-24$

$A=60\ ft^2$

Part 2) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior square

The area of square is equal to

$A=b^2$

where

b is the length side of the square

so

$A=(12)(8)-(4^2)$

$A=96-16$

$A=80\ cm^2$

Part 3) we know that

The area of the shaded region is equal to the area of four rectangles plus the area of one square

so

$A=4(4)(5)+(4^2)$

$A=80+16$

$A=96\ m^2$

Part 4) we know that

The shaded region is equal to the area of the complete square minus the area of the interior square

so

$A=(15^2)-(9^2)$

$A=225-81$

$A=144\ cm^2$

Part 5) we know that

The area of the shaded region is equal to the area of triangle minus the area of rectangle

The area of triangle is equal to

$A=\frac{1}{2}(b)(h)$

where

b is the base of triangle

h is the height of triangle

so

$A=\frac{1}{2}(6)(7)-(6)(2)$

$A=21-12$

$A=9\ m^2$

Part 6) we know that

The area of the shaded region is equal to the area of the circle minus the area of rectangle

The area of the circle is equal to

$A=\pi r^{2}$

where

r is the radius of the circle

so

$A=\pi (7^2)-(3)(11)$

$A=(49\pi -33)\ in^2$

7 0

3 years ago

1.morgan is 15 years old younger than Mrs.santtos their combined age is 442. jenny won the ping-pong championship eight more tim

swat32

If Morgan is 15 years younger then Mrs.Santos and there combined age is 442 that means that Mrs.Santos is 221, and Morgan is 206.

8 0

3 years ago

The width of a slot of a duralumin forging is (in inches) normally distributed with μ= 0.9000 and σ = 0.0030. The specification

Lubov Fominskaja [6]

Answer:

a) 9.56%

b) 0.0019

Step-by-step explanation:

a) Find the z-scores.

z = (x − μ) / σ

z₁ = (-0.0050) / 0.0030

z₁ = -1.67

z₂ = (0.0050) / 0.0030

z₂ = 1.67

Find the probability using a chart or calculator.

P(Z < -1.67 or Z > 1.67) = 2 P(Z < -1.67)

P(Z < -1.67 or Z > 1.67) = 2 (0.0478)

P(Z < -1.67 or Z > 1.67) = 0.0956

b) Use a chart or calculator to find the z-score.

P(Z < -z or Z > z) = 0.01

P(Z < -z) = 0.005

z = 2.576

Find the standard deviation.

z = (x − μ) / σ

2.576 = (0.0050) / σ

σ = 0.0019

4 0

3 years ago

3<br> 100°<br> B.<br> 48<br> 270<br> o<br> ZA=<br> degrees<br> b=<br> (=

solong [7]

Answer:

Angle A = 53

Step-by-step explanation:

All triangles add up to 180 so...

Lets use x to describe angle A

100+27+x=180

127+x=180

x=53

I'm confused what its asking about b and c but hope this helps a bit :)

6 0

3 years ago