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suter [353]
3 years ago
6

A whale is at the surface of the ocean to breathe. What is the whale’s elevation?

Mathematics
2 answers:
aivan3 [116]3 years ago
5 0

Answer:

c

Step-by-step explanation:

kow [346]3 years ago
5 0

Answer is C

Because the surface is flat.

I hope that helps.

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James and Terry open a savings account that has a 2.75% annual interest rate, compounded monthly. They deposited $500 into the a
zhuklara [117]

Answer:

$275

Step-by-step explanation:

This is what I got:

You first <u>convert</u> 2.75% into 0.0275

You then <u>multiply</u> 500 x 0.0275 = 13.75

Finally you <u>multiply</u> 13.75 x 20 = 275

so the answer should be 275

5 0
4 years ago
Tax is 7.5%, how much tax will you pay on a suit that costs $350
Harlamova29_29 [7]
$376.25 tax added on is $26.25

3 0
3 years ago
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Andrew went to the store with $200.00. He bought 2 pair of shorts for $25.00 each, he bought 3 shirts for $22.00 each, and he bo
kap26 [50]
200-(25•2)=150
150-(22•3)=84
84-25=59
Andrew has $59 left
5 0
3 years ago
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Each solid is composed of a rectangular prism and a regular prism. Find the surface area of the solid.
Amanda [17]

1345 is answer but not sure

4 0
3 years ago
Find the equation of a line that is perpendicular to y = 3x – 5 and passes through the point (1, -3).
Svetradugi [14.3K]

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

\begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}\qquad \qquad y = \stackrel{\stackrel{m}{\downarrow }}{3}x-5

well then therefore

\stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{3\implies \cfrac{3}{1}} ~\hfill \stackrel{reciprocal}{\cfrac{1}{3}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{1}{3}}}

so we're really looking for the equation of a line with slope of -1/3 and that passes through (1, -3 )

(\stackrel{x_1}{1}~,~\stackrel{y_1}{-3})\qquad \qquad \stackrel{slope}{m}\implies -\cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{-\cfrac{1}{3}}(x-\stackrel{x_1}{1})\implies y+3=-\cfrac{1}{3}x+\cfrac{1}{3} \\\\\\ y=-\cfrac{1}{3}x+\cfrac{1}{3}-3\implies y=-\cfrac{1}{3}x-\cfrac{8}{3}

6 0
2 years ago
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