Ask question

Ask question

All categories

mrs_skeptik [129]

3 years ago

10

Triangle PQR is transformed to similar triangle P′Q′R′ below:

1 answer:

morpeh [17]3 years ago

6 0

1 over 3 should be the answer I think

You might be interested in

What is a domain mathamatics

dalvyx [7]

Answer:

In mathematics, the domain or set of departure of a function is the set into which all of the input of the function is constrained to fall. It is the set X in the notation f: X → Y, and is alternatively denoted as. . Since a function is defined on its entire domain, its domain coincides with its domain of definition.

Step-by-step explanation:

Google

5 0

3 years ago

Read 2 more answers

Find the area of the triangle base=8cm height= 5cm

mario62 [17]

Area= 1/2 base x height

Area= 1/2 8x5

Area= 40/2

Area= 20cm^2

8 0

3 years ago

Round 34,576 to the nearest thousand

VARVARA [1.3K]

Answer:

35000

Step-by-step explanation:

6 0

3 years ago

The region bounded by y=(3x)^(1/2), y=3x-6, y=0

Ganezh [65]

Answer:

4.5 sq. units.

Step-by-step explanation:

The given curve is $y = (3x)^{\frac{1}{2} }$

⇒ $y^{2} = 3x$ ...... (1)

This curve passes through (0,0) point.

Now, the straight line is y = 3x - 6 ....... (2)

Now, solving (1) and (2) we get,

$y^{2} - y - 6 = 0$

⇒ (y - 3)(y + 2) = 0

⇒ y = 3 or y = -2

We will consider y = 3.

Now, y = 3x - 6 has zero at x = 2.

Therefor, the required are = $\int\limits^3_0 {(3x)^{\frac{1}{2} } } \, dx - \int\limits^3_2 {(3x - 6)} \, dx$

= $\sqrt{3} [{\frac{x^{\frac{3}{2} } }{\frac{3}{2} } }]^{3} _{0} - [\frac{3x^{2} }{2} - 6x ]^{3} _{2}$

= $[\frac{\sqrt{3}\times 2 \times 3^{\frac{3}{2} } }{3}] - [13.5 - 18 - 6 + 12]$

= 6 - 1.5

= 4.5 sq. units. (Answer)

7 0

3 years ago

— 9y + 5у — 7y + Зу<br> I need help

Inessa05 [86]

Answer:

5gghbjfjhdjfjfifnrjfjfnfkfnf.jc79239nfkfnfjf

6 0

3 years ago