The value of A and B is 5 , 10 ;The average temperature for first ten hours is -7.466 degree F ; an expression for the rate that the temperature is changing with respect to h ; dt/dh = +B sin ((pi*h)/12)

<h3>What is a Function ?</h3>

A function is a mathematical statement used to correlate two variables.

The function given is

T(h) = - A - B * cos((pi*h)/12)

T is the temperature in degrees Fahrenheit and

h is the number of hours from midnight (0 <= h <= 24)

a. The initial temperature at midnight was - 15 degrees * F and

at Noon of New Year's Day it was 5 degrees * F

At midnight h = 0

T(h) = -15 degrees F

-15 = -A-B* cos 0

-15 = -A-B

A+B = 15------------------- (1)

At noon , h = 12 , T(h)= 5

- A - B* cos(pi) = 5

-A - B (-1) = 5

B -A = 5 ----------------------- (2)

Solving equation 1 and 2

2B = 20

B = 10

A = 5

The value of A and B is 5 , 10

The average temperature for first ten hours is -7.466 degree F

Find an expression for the rate that the temperature is changing with respect to h

dt/dh = +B sin ((pi*h)/12)

To know more about Function

brainly.com/question/12431044

#SPJ1

4 0

2 years ago

The difference between the roots of the quadratic equation x2+x+c=0 is 6. Find c.

NemiM [27]

We have that
$x_{1} - x_{2} = 6$
Let y be the first root, then y - 6 will be the second one. Since both roots make the quadratic equation equal to 0, we have that:
$y^{2} + y + c = (y - 6)^{2} + (y - 6) +c$
Solve for y:
$y^{2} +y +c = y^{2} - 12y + 36 + y - 6 +c \\ y + 12y - y = 30 \\ y = \frac{5}{2}$
Plug in y = 5/2 into original quadratic equation and solve for c:
$( \frac{5}{2}) ^{2} + \frac{5}{2} +c = 0 \\ c= - \frac{5}{2} - \frac{25}{4} \\ c = - \frac{35}{4}$
So, the answer is c = -35/4

6 0

4 years ago

How many different 2-digit numbers are there with the following property:the tenth digit is greater than the units digit?

Serggg [28]

Answer:

Step-by-step explanation:

Simply start by listing out the numbers from smallest to largest.

We start out with the smallest number following this information being the number 10. The next are 21 and 20. The next are 32, 31, and 30. We can start to see a pattern. If the ten's digit is n, then there are n numbers within that ten-group that have a greater 10's digit than unit's digit. The largest ten-group (90 to 98) has 9 integers following the rules established. Thus, the number of 2-digit integers that have ten's digits greater than units digit is 1+2+3+...+9=45

7 0

2 years ago