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Effectus [21]
3 years ago
11

Someone plz help me out

Mathematics
1 answer:
laila [671]3 years ago
8 0
One the first set, #1 figure, notice we have two angle tickmarks, so those angles are equal, however, notice at segment AB, is at the border of both triangles, so AB is just the same length for ∡ABC as it's for ∡ADB.

so, we have an Angle, then a Side, and then an Angle, so they're congruent by ASA.

now, on the 2nd set, #2 figure, we have an angle tickmark and a side tickmark, hmmmmm but notice angles 1 and 2, they're just across from each other at that junction, therefore, angles 1 and 2 are vertical angles adn therefore are also equal.

so, we have a Side, then an Angle and then another Side, the triangles are congruent by SAS.
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Step-by-step explanation:

Vertical asymptote can be Identites if there is a factor only in the denominator. This means that the function will be infinitely discounted at that point.

For example,

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Horizontal:

If we have a function like this

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Remember a constant can be represent by

a \times  {x}^{0}

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1 = 1 \times  {x}^{0}

2 =  2 \times {x}^{0}

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and

x =  {x}^{1}

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Look at the degrees, since the numerator has a smaller degree than the denominator, the denominator will grow larger than the numerator as x gets larger, so since the larger number is the denominator, our y values will approach 0.

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x =  \frac{3}{1}

Finally, if the numerator has a greater degree than denominator, the value of horizontal asymptote will be larger and larger such there would be no horizontal asymptote instead of a oblique asymptote.

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