One the first set, #1 figure, notice we have two angle tickmarks, so those angles are equal, however, notice at segment AB, is at the border of both triangles, so AB is just the same length for ∡ABC as it's for ∡ADB.
so, we have an Angle, then a Side, and then an Angle, so they're congruent by ASA.
now, on the 2nd set, #2 figure, we have an angle tickmark and a side tickmark, hmmmmm but notice angles 1 and 2, they're just across from each other at that junction, therefore, angles 1 and 2 are vertical angles adn therefore are also equal.
so, we have a Side, then an Angle and then another Side, the triangles are congruent by SAS.
This is in slope-intercept form, so you can think of it as being y=mx+b. Invert m (the slope) and flip its sign, and then substitute the x and y values in and solve for b. The answer is y=7/2x-20.
By definition, the quartiles split the data into four equal parts. The first quartile (Q1) will have 25% of the data below it.
The second quartile is the exact same value as the median. This is because the median splits the data into two equal halves, i.e. is at the midpoint.
There's not enough info. We can determine that 25% of the company makes more than $60,000, but we don't know how many people total work at the company. This info is missing.
Subtract the third and first quartiles (Q3 and Q1) to get the interquartile range (IQR). So IQR = Q3 - Q1 = 45-21 = 24
Same idea as the previous problem. IQR = Q3 - Q1 = 316.5 - 124.5 = 192
