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3 years ago

Kara found two websites that she could use to download songs.

Mathematics

2 answers:

Yuliya22 [10]3 years ago

7 0

Answer:

Step-by-step explanation:

Gnesinka [82]3 years ago

5 0

The answer is c because if you add it you’ll get that & that’s the only that makes sense.

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A company that makes mirrors sends their slightly flawed products to a discount store. This week, the company sent four mirrors

Vedmedyk [2.9K]

Answer:

mirror 4

Step-by-step explanation:i just did the quiz and got it right

5 0

2 years ago

Read 2 more answers

18,12,8,..<br><br> Find the 10th term

Leya [2.2K]

Answer:

$0.46822130$

Explanation:

The sequence is: $a_{n} =\frac{18 *2^{n-1} }{3^{n-1} }$ , where n = term wanted

$a_{10} =0.46822130$

7 0

2 years ago

6th grade math help me pleaseeeee

Ivenika [448]

Answer:

This is the answer of your question. ☺☺

Step-by-step explanation:

24 -37*2

24-74

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3 0

2 years ago

Finding an Equation of a tangent Line in Exercise, find an equation of the tangent line to the graph of the function at the give

frutty [35]

Answer:

$y=\dfrac{3x}{e}+\dfrac{4}{e}$

this is the equation of the tangent at point (-1,1/e)

Step-by-step explanation:

to find the tangent line we need to find the derivative of the function g(x).

$g(x) =e^{x^3}$

we know that $\frac{d}{dx}(e^{f(x)})=e^{f(x)}f'(x)$

$g'(x) =e^{x^{3}}(3 x^{2})$

$g'(x) =3 x^{2} e^{x^{3}}$

this the equation of the slope of the curve at any point x and it also the slope of the tangent at any point x. hence, g'(x) can be denoted as 'm'

to find the slope at (-1,1/e) we'll use the x-coordinate of the point i.e. x = -1

$m =3 (-1)^{2} e^{(-1)^{3}}\\m =3e^{-1}\\m=\dfrac{3}{e}$

using the equation of line:

$(y-y_1)=m(x-x_1)$

we'll find the equation of the tangent line.

here (x1,y1) =(-1,1/e), and m = 3/e

$(y-\dfrac{1}{e})=\dfrac{3}{e}(x+1)\\y=\dfrac{3x}{e}+\dfrac{3}{e}+\dfrac{1}{e}\\$

$y=\dfrac{3x}{e}+\dfrac{4}{e}$

this is the equation of the tangent at point (-1,1/e)

3 0

2 years ago

Tell whether the statement is always, sometimes, or never true. The LCM of two different prime numbers is their product.

Blizzard [7]

Answer:

Step-by-step explanation:The LCM of two or more prime numbers is equal to their product. ... Assume two prime numbers as two different variables and find their LCM using prime factorization of both the numbers.

3 0

2 years ago