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Monica [59]
3 years ago
6

Question 14. A carousel makes one complete revolution every 75 seconds. Levi sits on the carousel 4 feet from its center. If the

length of a carousel ride is 5 minutes, how many feet did Levi travel? E. 4 F. 16 G. 8π H. 32π
Mathematics
1 answer:
garik1379 [7]3 years ago
3 0

Answer:

The correct option is;

H. 32·π

Step-by-step explanation:

The given information are;

The time duration for one complete revolution = 75 seconds

The distance from the center of the carousel where Levi sits = 4 feet

The time length of a carousel ride = 5 minutes

Therefore, the number of complete revolutions, n, in a carousel ride of 5 minutes is given by n = (The time length of a carousel ride)/(The time duration for one complete revolution)

n = (5 minutes)/(75 seconds) = (5×60 seconds/minute)/(75 seconds)

n = (300 s)/(75 s) = 4  

The number of complete revolutions - 4

The distance of 4 complete turns from where Levi seats = 4 ×circumference of circle of Levi's motion

∴ The distance of 4 complete turns from where Levi seats = 4 × 2 × π × 4 = 32·π.

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When the snail crawls 1/2 of a mile per day, it will take him, $1 \times \frac{2}{1} \times 3$

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When the snail crawls 1/3 of a mile per day, it will take him, $1 \times \frac{3}{1} \times 3$

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When the snail crawls 1/4 of a mile per day, it will take him, $1 \times \frac{4}{1} \times 3$

   = 12 days to get to the next pond.

When the snail crawls 3/4 of a mile per day, it will take him, $1 \times \frac{4}{3} \times 3$

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When the snail crawls 2/3 of a mile per day, it will take him, $1 \times \frac{3}{2} \times 3$

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Answer:

Two equal sides = 14.4 inches each

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Step-by-step explanation:

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then:

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