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3 years ago

Determine if the equation defines y as a function of x: y2 = x2. yes or no

Mathematics

1 answer:

Alisiya [41]3 years ago

5 0

Answer:

no it's not, since y has two functions , a positive and negative in terms of x.

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Four ninths plus nine eighteenths :]

goldenfox [79]

Answer: 17/18

In words, this is seventeen eighteenths

==========================================

Work Shown:

4/9 + 9/18

8/18 + 9/18 ... see note below

(8+9)/18

17/18

----------------

note: To go from 4/9 to 8/18, we multiply top and bottom by 2. So that's why 4/9 = 8/18.

The diagram below shows a visual representation of why 4/9 = 8/18.

In the top row, I've drawn out 9 rectangles of the same size. Then I've shaded 4 of the 9 rectangles to represent the fraction 4/9. In the bottom row, I've cut each of those 9 rectangles into two smaller equal pieces, so we have 9*2 = 18 rectangles now. Note how the shaded regions are the same size, so this shows 4 green regions doubles to 2*4 = 8 yellow regions; therefore 4/9 is the same as 8/18.

8 0

2 years ago

I'LL MARK BRAINLIEST IF U HELP

neonofarm [45]

Answer:

3 times

Step-by-step explanation:

heaviest : 9/10 kg.. 0.9kg

lightest : 3/10 kg.... 0.3kg

0.3/0.9 = 1/3

3 0

2 years ago

6.Suppose the Gallup Organization wants to estimate the population proportion of those who think there should be a law that woul

drek231 [11]

Answer:

A sample of $n = (\frac{1.96\sqrt{0.3696*0.6304}}{E})^2$ is needed, in which E is the desired margin of error, as a proportion. If we find a decimal value, we round up to the next whole number.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is of:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

In a previous study of 1012 randomly chosen respondents, 374 said that there should be such a law.

This means that $n = 1012, \pi = \frac{374}{1012} = 0.3696$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

How large a sample size is needed to be 95% confident with a margin of error of E?

A sample size of n is needed, and n is found when M = E.

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$E = 1.96\sqrt{\frac{0.3696*0.6304}{n}}$

$E\sqrt{n} = 1.96\sqrt{0.3696*0.6304}$

$\sqrt{n} = \frac{1.96\sqrt{0.3696*0.6304}}{E}$

$(\sqrt{n})^2 = (\frac{1.96\sqrt{0.3696*0.6304}}{E})^2$

$n = (\frac{1.96\sqrt{0.3696*0.6304}}{E})^2$

A sample of $n = (\frac{1.96\sqrt{0.3696*0.6304}}{E})^2$ is needed, in which E is the desired margin of error, as a proportion. If we find a decimal value, we round up to the next whole number.

4 0

3 years ago

Hi please help me with this please help me draw the graph pls

sukhopar [10]

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