Subtracting the second equation by 18 on both sides, we have xy=-18. Next, we divide both sides by x to get y=-18/x Plugging that into the first equation, we have x+2(-18/x)=9. Multiplying both sides by x, we get x^2-36=9x. After that, we subtract both sides by 9x to get x^2-9x-36=0. Finding 2 numbers that add up to -9 but multiply to -36, we do a bit of guess and check to find the answers to be -12 and 3. Factoring it, we get
x^2-12x+3x-36=x(x-12)+3(x-12)=(x+3)(x-12). To find the x values, we have to find out when 0=(x+3)(x-12). This is simple as when you multiply 0 with anything, it is 0. Therefore, x=-3 and 12. Plugging those into x=-18/y, we get x=-18/y and by multiplying y to both sides, we get xy=-18 and then we can divide both sides by x to get -18/x=y. Plugging -3 in, we get -18/-3=6 and by plugging 12 in we get -18/12=-1.5. Therefore, our points are (-3,6) and (12, -1.5)
Answer:
1. D y = 8
2. C y = −8
Step-by-step explanation:
1.Both points have y-coordinate 8, so the line is horizontal.
A horizontal line has equation y = k
where k is the y-coordinate of all of its points.
The y-coordinate of all points on this line is 8.
Answer: y = 8
2.A line with 0 slope is a horizontal line. All points on a horizontal line have the same y-coordinate.
A horizontal line has equation
y = k
where k is the y-coordinate of all of its points.
The y-coordinate of the given point is -8, so all points must have -8 as the y-coordinate.
Answer: y = -8
Answer:
It has a maximum
Step-by-step explanation:
The way I think about it is looking at "a" (the leading variable's coefficient, so __x²), if it's negative, the graph is a frown, but if it's positive, it's a smile. In this case, a is -2, so the graph would have the shape of a frown, which has a maximum.
I hope this helped!
The solution is (1,3). This is where the two lines intersect.
(24xy^3-16x^2y^2+32x^2y)/8xy
<span><span>(<span><span><span><span><span><span><span>24x</span><span>y^3</span></span>−<span><span>16<span>x^2</span></span><span>y^2</span></span></span>+<span><span>32<span>x^2</span></span>y</span></span>8</span></span>x</span>)</span><span>(y)</span></span><span> =<span><span><span>−<span><span>2<span>x^3</span></span><span>y^3</span></span></span>+<span><span>3<span>x^2</span></span><span>y^4</span></span></span>+<span><span>4<span>x^3</span></span><span>y^<span>2</span></span></span></span></span>
