Y=5x-4
3y=15x-8
3(5x-4)=15x-8
15x-12=15x-8
??
Therefore, there is no solution.
Answer:
The answer is 
.
Step-by-step explanation:
First, it is important to recall that the group law is not commutative in general, so we cannot assume it here. In order to solve the exercise we need to remember the axioms of group, specially the existence of the inverse element, i.e., for each element 
there exist another element, denoted by 
such that 
, where 
stands for the identity element of G.
So, given the equality 
we make a left multiplication by 
and we obtain:
But, 
. Hence, 
.
Now, in the equality we make a right multiplication by 
, and we obtain
.
Recall that 
and 
. Therefore,
.
The consecutive positive integers would be: x and (x+1),
We would have to solve the following equation to find these numbers:
x(x+1)-[x+(x+1)]=29
x²+x-2x-1=29
x²-x-30=0
x=[1⁺₋√(1+120)]/2
x=(1⁺₋11)/2
We have two possible solutions:
x₁=(1-11)/2=-5 then: (x+1)=-5+1=-4 This is not the solution.
x₂=(1+11)/2=6 then: (x+1)=6+1=7 This solution is right.
Answer: the numbers would be 6 and 7.
Answer:
It would be 68,70,72
Step-by-step explanation:
The sum of first and third of 3 consecutive number is 140 as 68+72 is 140.
68 is the first
72 is the third
They are all even numbers as well
Answer:
-4
Step-by-step explanation:
6 - 2x = 3
-2x = 3 + 6
-2x = 8
x= 
x= -4
I apologize if this isn't the right answer.
