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solong [7]
3 years ago
14

What theorem can be used to prove that the two triangles are congruent?

Mathematics
1 answer:
choli [55]3 years ago
6 0
The answer is D)
SSS
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1.Scale Factor : 4
Montano1993 [528]

Answer:

need points sorry

Step-by-step explanation:

5 0
2 years ago
What is the value of n in the equation 1 (n – 4) – 3 = 3 - (2n+3)?
xxTIMURxx [149]

Answer:

n=7/3

Step-by-step explanation:

1 (n – 4) – 3 = 3 - (2n+3)

1. distribute the 1 on the left side and distribute the -1 on the right side

1n-4-3=3-2n-3

2. add like terms

1n-7=-2n

3. move n to one side and by itself

-7=-3n

4. divide -3 to get n alone. Both negatives cancel out each other

7/3=n

4 0
3 years ago
Read 2 more answers
You eat 18 grams of your daily carbohydrates which is 6% of daily needs what is your daily need
adell [148]

Answer:

300 grams

Step-by-step explanation:

To find the total  number of carbohydrates, you need to find what fraction 6 is of 100, so you can do 100/6, but I just did 18* 100/6 right away, so that you can find 18* the fraction that 6 is of 100. The answer that I got is 300 grams. Hope this helps!

7 0
3 years ago
Original Equation:8 - 7x^2 + 3 = 4x^2 - 1Frist step:11 - 7x^2 = -4x^2 - 1Which property justifies the first step?A. Division pro
Tpy6a [65]

8 - 7x^2 + 3 = 4x^2 - 1

8+3-7x^2 = 4x^2-1

11-7x^2 = 4x^2-1

B. Commutative property of addition

We can swap numbers and obtain the same results.

In this case, we swapped 8+3 and added them.

7 0
1 year ago
What is number 61 and a step by step explaination please?
astra-53 [7]

1/3 ln(<em>x</em>) + ln(2) - ln(3) = 3

Recall that m\log_b(n)=\log_b(n^m), so

ln(<em>x</em> ¹ʹ³) + ln(2) - ln(3) = 3

Condense the left side by using sum and difference properties of logarithms:

\log_b(m)+\log_b(n)=\log_b(mn)

\log_b(m)-\log_b(n)=\log_b\left(\dfrac mn\right)

Then

ln(2/3 <em>x</em> ¹ʹ³) = 3

Take the exponential of both sides; that is, write both sides as powers of the constant <em>e</em>. (I'm using exp(<em>x</em>) = <em>e</em> ˣ so I can write it all in one line.)

exp(ln(2/3 <em>x</em> ¹ʹ³)) = exp(3)

Now exp(ln(<em>x</em>)) = <em>x </em>for all <em>x</em>, so this simplifies to

2/3 <em>x</em> ¹ʹ³ = exp(3)

Now solve for <em>x</em>. Multiply both sides by 3/2 :

3/2 × 2/3 <em>x</em> ¹ʹ³ = 3/2 exp(3)

<em>x</em> ¹ʹ³ = 3/2 exp(3)

Raise both sides to the power of 3:

(<em>x</em> ¹ʹ³)³ = (3/2 exp(3))³

<em>x</em> = 3³/2³ exp(3×3)

<em>x</em> = 27/8 exp(9)

which is the same as

<em>x</em> = 27/8 <em>e</em> ⁹

3 0
3 years ago
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