How many males and how many females would there be if the total enrollment is 15000?
Ratio is
90 males 15000 - x
------------- = ---------------
125 fem x
Then 90x = 1875000 - 125x, or 215x = 1875000
x = approx 8720 females
and 15000-8720, or 6279 males
If every male finds a dance partner, that would leave (8720-6279) females, or 2440, without dance partners. ;(
Check: is the male:female ratio near 90:125?
Is 6279:8720 approx equal to 90:125?
Yes. 0.72 (approx) = 0.72 (approx).
4 = 7 - 3
1 = 4 - 3
-2 = 1 - 3
-5 = -2 - 3
=> An = A (n-1) - 3, where A1 = 7
The next term is A6 = A5 - 3 = - 5 - 3 = - 8
So the answer is the fourth option.
Answer:
EIM
Step-by-step explanation:
simentrical side cuting.then the other side also same area
Sure! I'll try!
2x + 29 +11 = x + 28
First, you would put like terms ( the x ) on the same side.
2x + 29 + 11 = x + 28
-2x -2x
Giving you: 29 + 11 = -3x + 28
Then, you would add 29 and 11 together to get 40.
Next, you'd put the 28 on the other side.
40 = -3x + 28
-28 - 28
Giving you: 12 = -3x
<em>The</em><em> </em><em>right</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>7</em><em> </em><em>degree</em><em>.</em>
<em>pl</em><em>ease</em><em> </em><em>see</em><em> </em><em>the</em><em> </em><em>attached</em><em> picture</em><em> for</em><em> full</em><em> solution</em>
<em>h</em><em>ope</em><em> it</em><em> helps</em>
