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2 years ago

6

A small bar of gold measures 20 mm by 150 mm by 2 mm. One cubic milimeter of gold weighs about 0.0005 ounces. Find the volume in

cubic millimeters and the weight in ounces of this small bar of gold.

1 answer:

Kay [80]2 years ago

6 0

Answer:

= 3oz

Step-by-step explanation:

v = 20mm ×150mm ×2mm = 6000 mm^3

so, the weight is

6000 mm^3 × 0 .0005oz/1mm^3 = 3oz

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A boy has in his pocket a 50-cent piece, two dimes and two pennies. If he pulls out a coin at random, what is the probability it

rodikova [14]

Well, from what I can tell he has 1 50 cent piece, 2 Dimes, and 2 Pennies. Meaning 5 objects in total, considering that it asks for "at least ten cents" that would mean the 2 Dimes and the 1 50 cent piece.
Since that is 3 objects out of the 5, being 3/5ths, that would mean he has a 60% chance or probability for the first draw.

Hopefully that helps. ^ ^
{-Ghostgate-}

3 0

3 years ago

Read 2 more answers

An SRS of 350 high school seniors gained an average of x¯=21 points in their second attempt at the SAT Mathematics exam. Assume

Lynna [10]

Answer:

a) $21-2.58\frac{52}{\sqrt{350}}=13.83$

$21+2.58\frac{52}{\sqrt{350}}=28.17$

So on this case the 99% confidence interval would be given by (13.83;28.17)

b) $ME=2.58\frac{52}{\sqrt{350}}=7.17$

c) $ME=2.58\frac{52}{\sqrt{100}}=13.42$

d) D. Decreasing the sample size increases the margin of error, provided the confidence level and population standard deviation remain the same.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Part a

$\bar X=21$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma=52$ represent the population standard deviation

n=350 represent the sample size

99% confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.005,0,1)".And we see that $z_{\alpha/2}=2.58$

Now we have everything in order to replace into formula (1):

$21-2.58\frac{52}{\sqrt{350}}=13.83$

$21+2.58\frac{52}{\sqrt{350}}=28.17$

So on this case the 99% confidence interval would be given by (13.83;28.17)

Part b

The margin of error is given by:

$ME=2.58\frac{52}{\sqrt{350}}=7.17$

Part c

The margin of error is given by:

$ME=2.58\frac{52}{\sqrt{100}}=13.42$

Part d

As we can see when we reduce the sample size we increase the margin of error so the best option for this case is:

D. Decreasing the sample size increases the margin of error, provided the confidence level and population standard deviation remain the same.

6 0

2 years ago

1/2x7 giving your answer as a mixed number

Aleksandr [31]

Answer:
3 and 1/2.
Step-by-step explanation:
1/2 times 7 = (7 times 1) / 2 = 7 / 2 = (6 + 1) / 2 = 3 and 1/2.
Hope this helps!

3 0

3 years ago

The Lacrosse booster club is holding a raffle for a fundraiser. They will sell 100 tickets for $5 each and select 4 winners. All

Nadusha1986 [10]

Answer:

<h2>There are 3,921,225 ways to select the winners.</h2>

Step-by-step explanation:

This problem is about combinations with no repetitions, because the same person can't win four times. It's a combinaction because the order of winning doesn't really matter.

Combinations without repetitions are defined as

$C_{n}^{r} =\frac{n!}{r!(n-r)!}$

Where $n=100$ and $r=4$ .

Replacing values, we have

$C_{100}^{4} =\frac{100!}{4!(100-4)!}=\frac{100!}{4! 96!}=\frac{100 \times 99 \times 98 \times 97 \times 96!}{4! \times 96!}= \frac{94,109,400}{24}= 3,921,225$

Therefore, there are 3,921,225 ways to select the winners.

Additionally, as you can imagine, the probability of winning is extremely low, it would be 3,921,225 to 1.

3 0

3 years ago

If x equals 4 what is the value of y in the example below <br><br> y= 1/4 4.

ddd [48]

Answer:

sorry i cant help

Step-by-step explanation:

6 0

3 years ago