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Contact [7]
2 years ago
6

A small bar of gold measures 20 mm by 150 mm by 2 mm. One cubic milimeter of gold weighs about 0.0005 ounces. Find the volume in

cubic millimeters and the weight in ounces of this small bar of gold.
Mathematics
1 answer:
Kay [80]2 years ago
6 0

Answer:

= 3oz

Step-by-step explanation:

v = 20mm ×150mm ×2mm = 6000 mm^3

so, the weight is

6000 mm^3 × 0 .0005oz/1mm^3 = 3oz

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A boy has in his pocket a 50-cent piece, two dimes and two pennies. If he pulls out a coin at random, what is the probability it
rodikova [14]
Well, from what I can tell he has 1 50 cent piece, 2 Dimes, and 2 Pennies. Meaning 5 objects in total, considering that it asks for "at least ten cents" that would mean the 2 Dimes and the 1 50 cent piece.
Since that is 3 objects out of the 5, being 3/5ths, that would mean he has a 60% chance or probability for the first draw.

Hopefully that helps. ^ ^
{-Ghostgate-}
3 0
3 years ago
Read 2 more answers
An SRS of 350 high school seniors gained an average of x¯=21 points in their second attempt at the SAT Mathematics exam. Assume
Lynna [10]

Answer:

a) 21-2.58\frac{52}{\sqrt{350}}=13.83  

21+2.58\frac{52}{\sqrt{350}}=28.17  

So on this case the 99% confidence interval would be given by (13.83;28.17)  

b) ME=2.58\frac{52}{\sqrt{350}}=7.17

c) ME=2.58\frac{52}{\sqrt{100}}=13.42

d) D. Decreasing the sample size increases the margin of error, provided the confidence level and population standard deviation remain the same.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Part a

\bar X=21 represent the sample mean  

\mu population mean (variable of interest)  

\sigma=52 represent the population standard deviation  

n=350 represent the sample size  

99% confidence interval  

The confidence interval for the mean is given by the following formula:  

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)  

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.005,0,1)".And we see that z_{\alpha/2}=2.58  

Now we have everything in order to replace into formula (1):  

21-2.58\frac{52}{\sqrt{350}}=13.83  

21+2.58\frac{52}{\sqrt{350}}=28.17  

So on this case the 99% confidence interval would be given by (13.83;28.17)  

Part b

The margin of error is given by:

ME=2.58\frac{52}{\sqrt{350}}=7.17

Part c

The margin of error is given by:

ME=2.58\frac{52}{\sqrt{100}}=13.42

Part d

As we can see when we reduce the sample size we increase the margin of error so the best option for this case is:

D. Decreasing the sample size increases the margin of error, provided the confidence level and population standard deviation remain the same.

6 0
2 years ago
1/2x7 giving your answer as a mixed number
Aleksandr [31]
Answer:
3 and 1/2.
Step-by-step explanation:
1/2 times 7 = (7 times 1) / 2 = 7 / 2 = (6 + 1) / 2 = 3 and 1/2.
Hope this helps!
3 0
3 years ago
The Lacrosse booster club is holding a raffle for a fundraiser. They will sell 100 tickets for $5 each and select 4 winners. All
Nadusha1986 [10]

Answer:

<h2>There are 3,921,225 ways to select the winners.</h2>

Step-by-step explanation:

This problem is about combinations with no repetitions, because the same person can't win four times. It's a combinaction because the order of winning doesn't really matter.

Combinations without repetitions are defined as

C_{n}^{r}  =\frac{n!}{r!(n-r)!}

Where n=100 and r=4.

Replacing values, we have

C_{100}^{4}  =\frac{100!}{4!(100-4)!}=\frac{100!}{4! 96!}=\frac{100 \times 99 \times 98 \times 97 \times 96!}{4! \times 96!}=  \frac{94,109,400}{24}= 3,921,225

Therefore, there are 3,921,225 ways to select the winners.

Additionally, as you can imagine, the probability of winning is extremely low, it would be 3,921,225 to 1.

3 0
3 years ago
If x equals 4 what is the value of y in the example below <br><br> y= 1/4 4.
ddd [48]

Answer:

sorry i cant help

Step-by-step explanation:

6 0
3 years ago
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