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Novay_Z [31]
3 years ago
7

Pls help!!! Which steps would you use to solve this equation? Check all that apply.

Mathematics
1 answer:
hram777 [196]3 years ago
3 0

Answer:

you subtract 7 from both sides

Step-by-step explanation:

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Use a standard normal table to find the positive critical value that corresponds to a right tail area of 0.0250.025​, rounding t
IRINA_888 [86]
Let the require value be x, then

P(z > x) = 0.025
1 - P(z < x) = 0.025
P(z < x) = 1 - 0.025 = 0.975
P(z < x) = P(z < 1.96)
x = 1.96

Therefore, <span>the positive critical value that corresponds to a right tail area of 0.025</span> is 1.96
4 0
3 years ago
Kiran and Clare live 24 miles away from each other along a rail trail. One Saturday, the two friends started walking toward each
vivado [14]

Answer:

They would be 44.6 miles apart

Step-by-step explanation:

Here, we want to calculate how far they will be in 1 hour

Mathematically;

Distance = speed * time

In 1 hour, Kiran would have traveled a distance of 3 * 1 = 3 miles

While Clare would have traveled a distance of 3.4 * 1 = 3.4 miles

Now, we want to calculate how far apart they would be

On the 24 miles trail, Kiran would be at a distance of 21 miles to the other end

On the 24 miles Claire would be at a distance of 20.6 miles

So how far apart they would be is

24 miles + 20.6 miles = 44.6 miles

3 0
2 years ago
Please help I don’t understand!
Olenka [21]

Answer:

16.7552

Step-by-step explanation:

The Area of a sector of a circle is θ/360 pi r²

so,

30/360 x 3.142 x 8 x 8

= 16.7551 to four decimal places is

8 0
2 years ago
Toni bought 5 t-shirts for $35 . Each shirts cost the same amount
nexus9112 [7]

Answer:

35/5 =7 dollars

8 0
3 years ago
Read 2 more answers
A population of insects grows exponentially, as shown in the table. Suppose the increase in population continues at the same rat
Ivanshal [37]

We are told that a population of insects grows exponentially and we are given a table of data about insect population growth. We are asked to find population of insects at the end of week 11.        

The initial insect population is 20 and at the end of 1st week population increases to 30.

Let us find growth percentage of insect  population,

\text{Growth percentage}=\frac{\text{Difference}}{Actual} \cdot100

\text{Growth percentage}=\frac{\text{30-20}}{20} \cdot100

\text{Growth percentage}=\frac{\text{10}}{20} \cdot100

\text{Growth percentage}=0.5 \cdot100=50

We can see that insect population is growing at rate of 50% per week.

Now let us write an exponential function for our population.

P(w)=20(1+0.50)^{w}, where P(w) represents population at the end of w weeks.

Let us substitute w=11 in our function to find insect population at the end of 11 weeks.

P(11)=20(1+0.50)^{11}

P(11)=20(1.50)^{11}

P(11)=20\cdot 86.49755859375

P(11)=1729.951171875\approx 1730

Therefore, population of insects at the end of 11th week will be 1730.  



7 0
3 years ago
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