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Soloha48 [4]
3 years ago
12

Help due in 30 min!!!!!!!!!!!!!!!

Mathematics
1 answer:
kvasek [131]3 years ago
6 0
The answer is no bc they all have the same x coordinate and therefore fail the vertical line test
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Please help me w ith thsi
gogolik [260]

Hi there! :)

\large\boxed{A = 12.5 \text{ units}^{2}}

Find the area of the shape using the formula for the area of a trapezoid:

A = 1/2(b1 + b2) · h

Where:

b1 = base 1

b2 = base 2

h = height

A = area

Plug in the given bases and height:

A = 1/2(7.5 + 2.5) · 2.5

Simplify:

A = 1/2(10) · 2.5

A = 5 · 2.5

A = 12.5 units²

6 0
3 years ago
Multiply. Express your answer in simplest form. 1/8 × 5/6
Vitek1552 [10]

Answer:

5/48

Step-by-step explanation:

1x5=5

8x6=48

which give u

5/48

5 0
4 years ago
Read 2 more answers
What is the value of |5 - 2x |- 13 /8when
ra1l [238]

Answer:

Use a calculator

Step-by-step explanation:

5 0
3 years ago
It took everly 55 minutes to run a 10-kilometer race late weekend. If you know that 1 kilometer equals 0.621 miles, how many min
Ket [755]
Well this type of problems isn't exactly my strong suit, but I tried to come up with a solution, so my reasoning is as follows: we know that 1km is 0.621 miles, and the problem incites us to find how much time 1 mile takes, so we need to find how many kms are in a mile:
                                          1km ---> 0.621 miles
                                   <=> 1/0.621=1.610 km ---> 0.621/0.621 = 1 mile
so 1 mile = 1.610 km
Next we need to know how much time 1.610 km takes to run across
We know that:
10 km take 55 mins
and 1.610 = 10/6.211
so we need to divide 55 by the same value
55/6.211 = 8.855 mins
So 10 km ---> 55 mins
      1.610 = 10/6.211 km ---> 55/6.211 = 8.855 mins

I hope I didn't mess up.
Hope I helped ^^
3 0
3 years ago
In △ABC,a=13, b=14, and c=18. Find m∠A.
aev [14]

Answer:

m∠A = 45.86°

Step-by-step explanation:

A rough sketch of the triangle is shown in the attached pic.

When 3 sides are given and we want to solve for an angle, we use the Cosine Rule. Which is:

p^2=a^2 +b^2 -2abCosP

Where a, b, p are the lengths of 3 sides (with p being the side opposite of the angle we are solving for) and P is the angel we want to solve for

Thus, we have:

p^2=a^2 +b^2 -2abCosP\\13^2=14^2 +18^2-2(14)(18)CosA\\169=520-504CosA\\504CosA=351\\CosA=\frac{351}{504}\\CosA=0.6964\\A=Cos^{-1}(0.6964)=45.86

7 0
4 years ago
Read 2 more answers
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