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3 years ago

15

3x + 1 − 4x3 + 6x6 −2x2 standard form

1 answer:

Molodets [167]3 years ago

7 0

<span>6x6 - 4x3 - 2x2 + 3x + 1</span>

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Yolanda create a garden that is 17 ft. She calculated that the area of the garden is 34 ft square. Is this correct

Phantasy [73]

There is no way of knowing because they did not specify if it’s 17ft high, 17ft width, or 17ft length so she is most likely wrong

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3 years ago

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Find the decimal of <br>49/50

Lerok [7]

0,98 ..................

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3 years ago

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A store sells flower arrangements at a cost of $28 each. Which statements are true regarding the price of the arrangements? Chec

Maru [420]

Let's check each case to determine the solution to the problem.

we know that

The cost of each flower arrangements is $\$28$

Statements

<u>case A)</u> If the price is marked down by $10$ percent, the new price will be $\$25.20$

we know that

If the price is marked down by $10$ percent

then

the new price will be

$10\%= \frac{10}{100} =0.10$

$(1-0.10)*\$28=0.90*\$28 \\= \$25.20$

$\$25.20=\$25.20$

therefore

The statement case A) is True

<u>case B)</u> If the price is marked down by $25$ percent, the new price will be $\$21$

we know that

If the price is marked down by $25$ percent

then

the new price will be

$25\%= \frac{25}{100} =0.25$

$(1-0.25)*\$28=0.75*\$28 \\= \$21$

$\$21=\$21$

therefore

The statement case B) is True

<u>case C)</u> If the price is marked down by $50$ percent, the new price will be $\$19$

we know that

If the price is marked down by $50$ percent

then

the new price will be

$50\%= \frac{50}{100} =0.50$

$(1-0.50)*\$28=0.50*\$28 \\= \$14$

$\$14 \neq \$19$

therefore

The statement case C) is False

<u>case D)</u> If the price is marked down by $35$ percent, the new price will be $\$18.20$

we know that

If the price is marked down by $35$ percent

then

the new price will be

$35\%= \frac{35}{100} =0.35$

$(1-0.35)*\$28=0.65*\$28 \\= \$18.20$

$\$18.20=\$18.20$

therefore

The statement case D) is True

<u>case E)</u> If the price is marked down by $40$ percent, the new price will be $\$29.80$

we know that

If the price is marked down by $40$ percent

then

the new price will be

$40\%= \frac{40}{100} =0.40$

$(1-0.40)*\$28=0.60*\$28 \\= \$16.80$

$\$16.80 \neq \$29.80$

therefore

The statement case E) is False

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2 years ago

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1. The measure of side c is 150 feet and the

devlian [24]

Answer:

Step-by-step explanation:

We need a picture of what you're talking about.

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3 years ago

Consider the following function. f(x) = 16 − x2/3 Find f(−64) and f(64). f(−64) = f(64) = Find all values c in (−64, 64) such th

VARVARA [1.3K]

Answer:

This does not contradict Rolle's Theorem, since f '(0) = 0, and 0 is in the interval (−64, 64).

Step-by-step explanation:

The given function is

$f(x)=16-\frac{x^2}{3}$

To find $f(-64)$ , we substitute $x=-64$ into the function.

$f(-64)=16-\frac{(-64)^2}{3}$

$f(-64)=16-\frac{4096}{3}$

$f(-64)=-\frac{4048}{3}$

To find $f(64)$ , we substitute $x=64$ into the function.

$f(64)=16-\frac{(64)^2}{3}$

$f(64)=16-\frac{4096}{3}$

$f(64)=-\frac{4048}{3}$

To find $f'(c)$ , we must first find $f'(x)$ .

$f'(x)=-\frac{2x}{3}$

This implies that;

$f'(c)=-\frac{2c}{3}$

$f'(c)=0$

$\Rightarrow -\frac{2c}{3}=0$

$\Rightarrow -\frac{2c}{3}\times -\frac{3}{2}=0\times -\frac{3}{2}$

$c=0$

For this function to satisfy the Rolle's Theorem;

It must be continuous on $[-64,64]$ .

It must be differentiable on $(-64,64)$ .

and

$f(-64)=f(64)$ .

All the hypotheses are met, hence this does not contradict Rolle's Theorem, since f '(0) = 0, and 0 is in the interval (−64, 64) is the correct choice.

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2 years ago

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