The number of students in 5th grade is 60, since 24% of 250 is 60.
Since 90 is 38% if 250, 38 is going to be the percent of all students in sixth grade.
20% of 250 is 50, so the percent of all students in seventh grade is 50.
Finally, 45 is 18% of 250, so 18 percent of all students are in eight grade.
Hope this helped :)
Answer:
Hopes it helps
Step-by-step explanation:
The Quadratic Polynomial is
2 x² +x -4=0
Using the Determinant method to find the roots of this equation
For, the Quadratic equation , ax²+ b x+c=0
(b) x²+x=0
x × (x+1)=0
x=0 ∧ x+1=0
x=0 ∧ x= -1
You can look the problem in other way
the two Quadratic polynomials are
2 x²+x-4=0, ∧ x²+x=0
x²= -x
So, 2 x²+x-4=0,
→ -2 x+x-4=0
→ -x -4=0
→x= -4
∨
x² +x² +x-4=0
x²+0-4=0→→x²+x=0
→x²=4
x=√4
x=2 ∧ x=-2
As, you will put these values into the equation, you will find that these values does not satisfy both the equations.
So, there is no solution.
You can solve these two equation graphically also.
The semicircle shown at left has center X and diameter W Z. The radius XY of the semicircle has length 2. The chord Y Z has length 2. What is the area of the shaded sector formed by obtuse angle WXY?
RADIUS = 2
CHORD = 2
RADIUS --> XY , XZ , WX
( BEZ THEY TOUCH CIRCUMFERENCE OF THE CIRCLES AFTER STARTING FROM CENTRE OF THE CIRCLE)
THE AREA OF THE SHADED SECTOR FORMED BY OBTUSE ANGLE WXY.
AREA COVERED BY THE ANGLE IN A SEMI SPHERE
Total Area Of The Semi Sphere:-
Area Under Unshaded Part .
Given a triangle with each side 2 units.
This proves that it's is a equilateral triangle which means it's all angles r of 60° or π/3 Radian
So AREA :-
Total Area - Area Under Unshaded Part
I believe it is 4 my good sir
Answer:
-66
Step-by-step explanation:
11 × (-6) = -66
