(8x^3y^3z^4)(7x^6z^6)

1 answer:

4 0

First you multiple 8x times 7x and get 56x and since 3y doesn't have another y so u Leave tht as 3y then you multiply 3z times 6z and get 18z then you multiply 4 times 6 and get 24 (56x^3y)(18z^24)

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Phantasy [73]

$\displaystyle\lim_{(x,y)\to(0,0)}\frac{\left(x+23y)^2}{x^2+529y^2}$

Suppose we choose a path along the $x$ -axis, so that $y=0$ :

$\displaystyle\lim_{x\to0}\frac{x^2}{x^2}=\lim_{x\to0}1=1$

On the other hand, let's consider an arbitrary line through the origin, $y=kx$ :

$\displaystyle\lim_{x\to0}\frac{(x+23kx)^2}{x^2+529(kx)^2}=\lim_{x\to0}\frac{(23k+1)^2x^2}{(529k^2+1)x^2}=\lim_{x\to0}\frac{(23k+1)^2}{529k^2+1}=\dfrac{(23k+1)^2}{529k^2+1}$

The value of the limit then depends on $k$ , which means the limit is not the same across all possible paths toward the origin, and so the limit does not exist.

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Lubov Fominskaja [6]

Angle B is the linear pairs with 60°, so the size is 180-60=120°

Angle ABC is the linear pair with 120°, so the size is 180-120-60°

Angle A corresponds to angle 60°, so they are equal

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