Question

The rectangle below has an area of x^2 - 9 square meters and a width of x - 3 meters.

Answer 1

Answer:

x+3

Step-by-step explanation:

Area of a rectangle is $L\cdot W$.

We know the width, W, is $x-3$ and we know the area is $x^2-9$.

Inputting this in our formula above we get:

$x^2-9=L(x-3)$

L is a an expression such that when you multiply it to $(x-3)$ gives you $(x^2-9)$.

$x^2-9$ is a difference of squares and can be factored using:

$a^2-b^2=(a-b)(a+b)$.

$x^2-9=(x-3)(x+3)$.

So L=x-3 and W=x+3.