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2 years ago

The rectangle below has an area of x^2 - 9 square meters and a width of x - 3 meters.

Mathematics

1 answer:

Rama09 [41]2 years ago

4 0

Answer:

x+3

Step-by-step explanation:

Area of a rectangle is $L\cdot W$ .

We know the width, W, is $x-3$ and we know the area is $x^2-9$ .

Inputting this in our formula above we get:

$x^2-9=L(x-3)$

L is a an expression such that when you multiply it to $(x-3)$ gives you $(x^2-9)$ .

$x^2-9$ is a difference of squares and can be factored using:

$a^2-b^2=(a-b)(a+b)$ .

$x^2-9=(x-3)(x+3)$ .

So L=x-3 and W=x+3.

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Given the linear correlation coefficient r and the sample size n, determine the critical values of r and use your finding to sta

Dafna11 [192]

Answer: r represents a significant linear correlation.

Step-by-step explanation:

GIven : Linear correlation coefficient: r = 0.543

Sample size: n= 25

Significance levle: $\alpha=0.05$

Degree of freedom : n-2 = 25-2=23

Now, we check r critical value table for value with df = 23 and $\alpha=0.05$ .

Critical value = ±0.396 [From r critical value table]

Since r = 0.543 > 0.396, that means there is significant linear correlation.

Hence, r represents a significant linear correlation.

8 0

3 years ago

Please answer!! 20 points ASAP

lidiya [134]

Answer:

The length of VI to the nearest tenth is 4 cm

Solution:

The plot is like a quadrilateral and the fences are built on the diagonal

We know that for quadrilateral both the diagonals are in same height,

So as per the picture, $\mathrm{GH}=\mathrm{Fl}$

Now we know that $\mathrm{GV}=6.55 cm; \mathrm{FV}=5.84 cm; \mathrm{VH}=3.27 cm$

Hence,

$GH = FI$

$\Rightarrow GV + VH = VI + VF$

$\Rightarrow 6.55 + 3.27 = VI + 5.84$

$\Rightarrow VI = 6.55 + 3.27 - 5.84$

$\Rightarrow VI = 3.98$

Rounding off:

If the number that we are rounding is followed by 5 to 9, then the number has to be increased to the next successive number.

If the number that we are rounding is followed by 1 to 4, then the number has to remain the same.

Here the number to be round off is 3.98, 9 belongs to the first category stated above. So, 3 is increased to 4.

Hence, the length of VI = 4 cm.

7 0

3 years ago

Can you help me find the volume base area latera area and total area please to this problem

krek1111 [17]

Answer:

BA = 25π,

LA = 25√2π,

TA = 25π + 25√2π,

V = 41 and 2 / 3π

Step-by-step explanation:

We need to determine the height here, as it is not given, and is quite important to us. The height is a perpendicular line segment to the radius, hence forming a 45 - 45 - 90 degree triangle as you can see. Therefore, by " Converse to Base Angles Theorem " the height should be equal in length to the radius,

( Height = 5 inches = Radius

______

Now knowing the height, let's begin by calculating the base area. By it's name, we have to find the area of the base. As it is a circle, let us apply the formula " πr^2 "

$\pi r^2\\= \pi ( 5 )^2\\= 25\pi$ - Base Area = 25π

______

The lateral area is simply the surface area excluding the base area, the surface area having a formula of " πr^2 + πrl. " Thus, the lateral area can be calculated through the formula " πrl, " but as we are not given the slant height ( l ) we have to use another formula, $l= \sqrt{r^2+h^2}$ -

$\pi r( \sqrt{r^2+h^2} )\\= \pi( 5 )( \sqrt{5^2 + 5^2} )\\= 25\sqrt{2} \pi$ - Lateral Area = 25√2π

______

And the surface area is the base area + lateral area -

$25\pi + 25\sqrt{2} \pi$ - Surface Area

______

The volume of a cone is 1 / 3rd that of a cylinder, with a simple formula of Base * height. Therefore, we can conclude the following -

$1 / 3( 25\pi )( 5 )\\= 25 / 3( 5 )( \pi )\\= 41 \frac{2}{3}\pi$ - Volume = 41 and 2 / 3π

8 0

2 years ago

Please help help help help help help

nevsk [136]

Answer:

y is equal to (-1/4)x

hope this helped! :)

7 0

2 years ago

Sally says it is possible to draw a triangle with these side length

professor190 [17]

Step-by-step explanation:

The longest side of a triangle cannot be longer than the sum of the two shorter sides. So if the 5cm and 12cm sides are the shorter sides, the third one cannot be longer than the 17cm. ... So 12cm is not longer than 5cm plus the length of the third side, and therefore the missing side cannot be shorter than 7cm.

7 0

2 years ago