Question

The first discount on a camera was 18%. The second discount was 20%. After these two discounts the price was $328. What was the original price?

Answer 1

Answer:

$500

Step-by-step explanation:

We can find the original price of the camera through a proportion. A proportion is an equation where two ratios or fractions are equal. The ratios or fractions compare like quantities.

Second Discount

20% off means we paid 80%. We know we paid $328 of some price.

$\frac{80}{100} =\frac{328}{y}$

I can now cross-multiply by multiplying numerator and denominator from each ratio.

$80y=100(328)\\80y=32800$

I now solve for y by dividing by 80.

$\frac{80y}{80} =\frac{32800}{80} \\y= 410$

The price after the first discount was $410.

First Discount

We will repeat the steps above with $410. 18% off means we paid 82%.

$\frac{82}{100} =\frac{410}{y}$

I can now cross-multiply by multiplying numerator and denominator from each ratio.

$82y=100(410)\\82y=41000$

I now solve for y by dividing by 82.

$\frac{82y}{82} =\frac{41000}{82} \\y= 500$

The original price was $500.