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Drupady [299]
4 years ago
12

Where is the transverse axis of the hyperbola x^2-4y^2=16

Mathematics
1 answer:
Anton [14]4 years ago
3 0
 <span> <span>x^2-4y^2=16</span></span>

In this type of equations, having more than one variable (unknown), you have to specify for which variable you want the equation solved.
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Why does -6 - (-2) equal -4?
lukranit [14]

Answer:

when you subtract a negative number the two negative signs cancel out and it turns to a positive number

Step-by-step explanation:

in -6 - (-2)

the two - signs cancel out so it ends up being

-6+2 which is why it equals -4

8 0
3 years ago
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Which number line shows the sum of -8, 4, and -2?
Strike441 [17]

D is answer...........mmm

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3 years ago
Which expression is equivalent??? help!
dexar [7]

Answer:

The equivalent expression for the given expression \sqrt[3]{256x^{10}y^{7} } is

4x^{3} y^{2}(\sqrt[3]{4xy} )

Step-by-step explanation:

Given:

\sqrt[3]{256x^{10}y^{7} }

Solution:

We will see first what is Cube rooting.

\sqrt[3]{x^{3}} = x

Law of Indices

(x^{a})^{b}=x^{a\times b}\\and\\x^{a}x^{b} = x^{a+b}

Now, applying above property we get

\sqrt[3]{256x^{10}y^{7} }=\sqrt[3]{(4^{3}\times 4\times (x^{3})^{3}\times x\times (y^{2})^{3}\times y   )} \\\\\textrm{Cube Rooting we get}\\\sqrt[3]{256x^{10}y^{7} }= 4\times x^{3}\times y^{2}(\sqrt[3]{4xy}) \\\\\sqrt[3]{256x^{10}y^{7} }= 4x^{3}y^{2}(\sqrt[3]{4xy})

∴ The equivalent expression for the given expression \sqrt[3]{256x^{10}y^{7} } is

4x^{3} y^{2}(\sqrt[3]{4xy} )

5 0
3 years ago
Which angles are adjacent angles to 3? Select all that apply
sattari [20]

Two Answers: Angle 1, Angle 4

Adjacent angles share a common segment, line, or ray. Think of two adjacent rooms sharing a common wall.

3 0
3 years ago
Question 3<br> 1 pts<br> 2 and -2 are 4 units apart on the number line.<br> True<br> False
EastWind [94]
It’s actually true!

^ ^ ^ ^
<—|——|——|——|——|—>
-2 -1 0 1 2

The 4 arrows above the number line represents the distance between 2 and -2 which is 4!
4 0
3 years ago
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