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Drupady [299]
3 years ago
12

Where is the transverse axis of the hyperbola x^2-4y^2=16

Mathematics
1 answer:
Anton [14]3 years ago
3 0
 <span> <span>x^2-4y^2=16</span></span>

In this type of equations, having more than one variable (unknown), you have to specify for which variable you want the equation solved.
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How do you factor this trinomial 4a^2-4a+1
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Answer:

(2a-1)(2a-1)

Step-by-step explanation:

To write the factored form, multiply a*c from the standard form ax^2+bx+c. Here it is 4*1 = 4.

Then find factors of 4 that add to b=-4.

4: 1,2,4

-2+-2 = -4

Split the middle term into -2x+-2x and factor by grouping.

4a^2-2a+-2a+1\\(4a^2-2a)+(-2a+1)\\2a(2a-1)-1(2a-1)\\(2a-1)(2a-1)


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What is the solution for the equation 6x − 8 = 4x? x = . (Input whole number only). (5 points) Blank 1:
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Step-by-step explanation:

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6x - 8 = 4x        Equation

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Hope This Helps :)

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