Answer any of the following:

1 answer:

Volgvan3 years ago

4 0

1. Solve the system by substitution -2x+y=-11, 3x-4y=11.
-2x+y=-11
y = 2x-11

3x-4y=11
3x-4(2x-11)=11
3x -8x + 44 = 11
-5x = -33
x =33/5
y = 11/5

2. Solve the system using elimination- 2x+6y=-12, 5x-5y=10.
(-2x+6y=-12)5
-10x + 30y = -60

(5x-5y=10)2
10x - 10y = 20

Adding the two equations,
-10x + 30y = -60
10x - 10y = 20

20y = -40
y = -2
x = 0

3. What is the solution of the following system?-3x-2y=-12, 9x+6y=-9.
-3x-2y=-12
y = -3/2 x + 6

9x+6y=-9
y = -3/2 x - 3/2

Since the slopes are equal then they are parallel lines so they never meet at one point.

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What is the solution to this system of equations?

Maurinko [17]

Answer:

(x, y) = (5, -2)

Step-by-step explanation:

A graphing calculator provides a quick and easy way to find the solution.

_____

There are several other ways to solve these equations. Or you can estimate where the answer might be using logic like this:

The intercepts of the first equation are ...

x-intercept = 26/4 = 6 1/2
y-intercept = -26/3 = -8 2/3

So the graph of it will form a triangle with the axes in the 4th quadrant.

The intercepts of the second equation are ...

x-intercept = 11/3 = 3 2/3
y-intercept = 11/2 = 5 1/2

So the graph of it will form a triangle with the axes in the 1st quadrant. The x-intercept of this one is less than the x-intercept of the first equation, so the two lines must cross in the 4th quadrant.

The only 4th-quadrant answer choice is (5, -2).