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Vilka [71]
3 years ago
15

Suppose that you have 11 cards. 5 are green and 6 are yellow. The 5 green cards are numbered 1, 2, 3, 4, and 5. The 6 yellow car

ds are numbered 1, 2, 3, 4, 5, and 6. The cards are well shuffled. You randomly draw one card.
• G = card drawn is green
• Y = card drawn is yellow
• E = card drawn is even-numbered

a. List the sample space.
b. Enter probability P(G) as a fraction
c. P(G/E)
d. P(G AND E)
e. P(G or E)
f. Are G and E are mutually exclusive
Mathematics
1 answer:
Ivanshal [37]3 years ago
5 0

Answer:

a. S={G1,G2,G3,G4,G5,Y1,Y2,Y3,Y4,Y5,Y6}

b. P(G)=5/11

c. P(G/E)=2/5 or 0.4

d. P(G and E)=2/11 or 0.1818

e. P(G or E)=8/11 or 0.7273

f. G and E not mutually exclusive

Step-by-step explanation:

G={G1,G2,G3,G4,G5}

n(G)=5

Y={Y1,Y2,Y3,Y4,Y5,Y6}

n(Y)=6

E={G2,G4,Y2,Y4,Y6}

n(E)=5

a)

The possible outcomes in sample space are

S={G1,G2,G3,G4,G5,Y1,Y2,Y3,Y4,Y5,Y6}

b)

P(G)=n(G)/n(S)=5/11

c)

P(G/E)=P(G and E)/P(E)

G and E={G2,G4}

n(G and E)=2

P(G and E)=n(G and E)/n(S)=2/11

P(E)=n(E)/n(S)=5/11

P(G/E)=2/5

d)

G and E={G2,G4}

n(G and E)=2

P(G and E)=n(G and E)/n(S)=2/11

e)

P(G or E)= P(G)+P(E)-P(G and E)

P(G or E)=5/11+5/11-2/11

P(G or E)=8/11

f)

G and E are not mutually exclusive because G and E have 2 outcomes in common.

G and E={G2,G4}

Thus, P(G and E)≠0 and G and E are not mutually exclusive events

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Answer:

Answer in the explanation section

Step-by-step explanation:

Even numbers create symmetry, but odd numbers create interest. An odd number of details is more effective at capturing your gaze. Odd numbers force your eyes to move around the grouping and by extension, the room. That forced movement is the heart of visual interest.

An even number is a number that can be divided into two equal groups. An odd number is a number that cannot be divided into two equal groups. Even numbers end in 2, 4, 6, 8 and 0 regardless of how many digits they have (we know the number 5,917,624 is even because it ends in a 4!). Odd numbers end in 1, 3, 5, 7, 9.

To me i think Odd numbers have more power

if this is wrong i'm sorry

Hope this helps

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3 years ago
Two trains start from Fort Worth traveling at the same speed. The trip for Train W takes 20 hours, while the trip for Train Z ta
MrMuchimi

Answer:

The equation that best models this situation is :

b. \frac{x}{20}=\frac{x+400}{25}

Distance traveled by Train W = 1600 miles

Distance traveled by Train Z = 2,000 miles

Step-by-step explanation:

Given:

Time taken for Train W to complete a trip = 20 hours

Time taken for Train Z to complete a trip = 25 hours

The city Train Z is traveling to is 400 miles farther away than the city Train W is traveling to.

both trains have same speeds and start from same location.

To find the distance in total each train travels.

Solution:

<em>Let length of the trip of Train W be </em>= x miles

Speed of Train W can be given as :

⇒ \frac{Distance}{Time}

⇒ \frac{x}{20}\ miles/h

<em>So, the length of the trip of Train Z will be</em> = (x+400) miles

Speed of Train Z can be given as :

⇒ \frac{Distance}{Time}

⇒ \frac{x+400}{25}\ miles/h

Since the speeds are same, so the equation to find x can be given as:

⇒ \frac{x}{20}=\frac{x+400}{25}

Solving for x

Multiplying both sides by 100 to remove fractions.

⇒ 100\times \frac{x}{20}=100\times \frac{x+400}{25}

⇒ 5x=4(x+400)

Using distribution.

⇒ 5x=4x+1600

Subtracting both sides by 4x

⇒ 5x-4x=4x-4x+1600

⇒ x=1600

Thus, Distance traveled by Train W = 1600 miles

Distance traveled by Train Z = 1600+400 = 2,000 miles

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