All categories

3 years ago

Question in the image below:

Mathematics

1 answer:

horrorfan [7]3 years ago

4 0

Answer:

x = 5/33 or 0.151515151

Step-by-step explanation:

7(-6x-2) = 8(3x-4)

step 1: simplify the equation.

-42x - 14 = 24x - 4

step 2: isolate the variable (using the balance method).

-42x - 14 + 14 = 24x - 4 + 14

-42x = 24x + 10

-42x - 24x = 24x - 24x + 10

-66x = 10

step 3: solve for x.

x = 10 ÷ -66

x = 5/33

You might be interested in

5. Sketch the solution set of the system x > or equal to 0, y < 3, x - y > 1, y > 2x-1.

laiz [17]

Answer:

8w-ddje

Step-by-step explanation:

8 0

3 years ago

Please answer for me :

Arisa [49]

Answer:

Part A - $2\frac{1}{2} + b = 4\frac{2}{3}$

Part B - $2\frac{1}{6}$

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

10 points need help asap

alexandr402 [8]

Answer:

Cross section is the term name given to the front of any prism. SO, they are only found in a prism. They are recognized as the side/face that appears twice in a prism, and the shape have a visible length between these 2, known as the height

Step-by-step explanation:

Hope this helps

4 0

3 years ago

0.3(4+8)/-0.1+5/(9.2+13.2) HELP ME PLEASE!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

aleksklad [387]

0.3(4+8)/-0.1+5/(9.2+13.2)= -35.7767857143

8 0

2 years ago

how much would $150 invested at 8% interest compounded anually be worth after 13 years? A(t)=P(1+r/n)^

PIT_PIT [208]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$150\\
r=rate\to 8\%\to \frac{8}{100}\to &0.08\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &13
\end{cases}
\\\\\\
A=150\left(1+\frac{0.08}{1}\right)^{1\cdot 13}\implies A=150(1.08)^{13}\implies A\approx 407.9435589$

3 0

3 years ago