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Ivenika [448]
3 years ago
9

The amount of interest earned on a savings account varies directly with the amount of money saved. If $208 in interest is earned

on $6,500 of savings, how much interest will be earned on $8,000 of savings over the same time period?
Mathematics
1 answer:
Ne4ueva [31]3 years ago
6 0
8000/6500=x/208
Solve for x
X=256 earned on 8000
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Two cars start driving in the same direction from the same place. If one travels 5050 mph and the other 5959 ​mph, how long will
vlabodo [156]

There is a 909 mph gap between the two cars. So if we can divide 3636 by 909 we get 4.


Answer: 4 Hours

8 0
3 years ago
QUETSION 6 PLS HELP MEE
Alborosie

Answer:

x= -15

Step-by-step explanation:

5 0
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What are the domain and range of each relation? Drag the answer into the box to match each relation. A mapping diagram. Element
ra1l [238]

Answer:

Domain: {−2, −1, 0, 2} Range: {−4, −2, 2}

Step-by-step explanation:

We have been given a mapping diagram as shown below:

X Y

-2 -4

-1 -2

0 2

2


For better view, you can check the attached mapping diagram.

From that diagram we have to find domain and range.

Domain contains only x values so domain will be:

Domain: {-2,-1,0,2}

Range contains only y values so range will be:

Range: {-4,-2,2}

We see that only third choice matches obtained values of domain and range.

Hence final answer is  Domain: {−2, −1, 0, 2} Range: {−4, −2, 2}

7 0
3 years ago
Evaluate -19.2 + 87.31 please shoe work!​
andrew11 [14]

Answer:

the answer is 68.11

Step-by-step explanation:

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6 0
3 years ago
Read 2 more answers
A certain region currently has wind farms capable of generating a total of 2200 megawatts (2.2 gigawatts) of power. Assuming win
sveta [45]

Answer:

<u>The correct answer is A. 4,818'000,000 kilowatt-hours per year and B. 481,800 households.</u>

Step-by-step explanation:

1. Let's review the information provided to us for solving the questions:

Power capacity of the wind farms = 2,200 Megawatts or 2.2 Gigawatts

2. Let's resolve the questions A and B:

Part A

Assuming wind farms typically generate 25​% of their​ capacity, how much​ energy, in​ kilowatt-hours, can the​ region's wind farms generate in one​ year?

2,200 * 0.25 = 550 Megawatts

550 Megawatts = 550 * 1,000 Kilowatts = 550,000 Kilowatts

Now we calculate the amount of Kilowatts per hour, per day and per year:

550,000 Kw generated by the farms means that are capable of produce 550,000 kw per hour of energy

550,000 * 24 = 13'200,000 kilowatt-hours per day

<u>13'200,000 * 365 = 4,818'000,000 kilowatt-hours per year</u>

Part B

Given that the average household in the region uses about​ 10,000 kilowatt-hours of energy each​ year, how many households can be powered by these wind​ farms?

For calculating the amount of households we divide the total amount of energy the wind farms can generate (4,818'000,000 kilowatt-hours) and we divide it by the average household consumption (10,000 kilowatt-hours)

<u>Amount of households =  4,818'000,000/10,000 = 481,800</u>

8 0
4 years ago
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