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2 years ago

100 POINTS I NEED HELP ASAP If h(x) = |2x-4| , find (h-7)

Mathematics

2 answers:

aleksandrvk [35]2 years ago

8 0

The answer is 18.

Sorry no explanation im soooo sorry

nikitadnepr [17]2 years ago

7 0

Answer:

The answer is 18.

Step-by-step explanation:

You just need to plug in -7 to the equation 2x-4. You get -18, but absolute value is always positive, so its 18.

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Which polynomials are in standard form?

Leni [432]

Answer:

B:x^4-8x^2-16

Step-by-step explanation:

B: $x^4-8x^2-16$ is in standard form.

4 0

2 years ago

Write two expressions where the solution is 19.6.

larisa86 [58]

If the the expression can have addition it is fairly simple. For example: 19+.6 or (19+.1)-.4

7 0

3 years ago

Evaluate the integral using the indicated trigonometric substitution. (use c for the constant of integration.) x^3 / sqrt x^2 +

slava [35]

$\displaystyle\int\frac{x^3}{\sqrt{x^2+49}}\,\mathrm dx$

Taking $x=7\tan\theta$ gives $\mathrm dx=7\sec^2\theta\,\mathrm d\theta$ , so that the integral becomes

$\displaystyle\int\frac{(7\tan\theta)^3}{\sqrt{(7\tan\theta)^2+49}}(7\sec^2\theta)\,\mathrm d\theta$
$=\displaystyle7^4\int\frac{\tan^3\theta\sec^3\theta}{\sqrt{49\tan^2\theta+49}}\,\mathrm d\theta$
$=\displaystyle7^3\int\frac{\tan^3\theta\sec^3\theta}{\sqrt{\tan^2\theta+1}}\,\mathrm d\theta$
$=\displaystyle7^3\int\frac{\tan^3\theta\sec^3\theta}{\sqrt{\sec^2\theta}}\,\mathrm d\theta$
$=\displaystyle7^3\int\frac{\tan^3\theta\sec^3\theta}{|\sec\theta|}\,\mathrm d\theta$

When $\sec\theta>0$ , we have

$=\displaystyle7^3\int\frac{\tan^3\theta\sec^3\theta}{\sec\theta}\,\mathrm d\theta$
$=\displaystyle7^3\int\tan^3\theta\sec^2\theta\,\mathrm d\theta$

and from here we can substitute $u=\tan\theta$ to proceed from here.

Quick note: When we set $x=7\tan\theta$ , we are implicitly enforcing $-\dfrac\pi2$ just so that the substitution can be undone later via $\theta=\tan^{-1}\dfrac x7$ . But note that over this domain, we automatically guarantee that $\sec\theta>0$ , so the absolute value bars can be dropped immediately.

6 0

2 years ago

Answer with detail. Please show work for all questions (worth 100 points plus ill mark brainliest) ^-^ Thanks!

polet [3.4K]

Answer:

see below

Step-by-step explanation:

The volume of a cylinder is given by

V = pi r^2 h

We can find the radius from the diameter

r = d/2 = 34/2 = 17

V = (3.14) (17)^2 * 27

V =24501.42 m^3

The surface of a cone is found by

SA = pi r^2 + pi r l where l is the slant height

We can find the radius from the diameter

r = 8/2 = 4

SA =(3.14) * 4^2 + 3.14 * 4*7

=50.24+87.92

138.16 in^2

The lateral surface area of a pyramid is found by taking the area of the sides

LSA = 4 * the area of a triangle

we multiply by 4 since there are 4 sides

= 4 * 1/2 b*h where b is the base of the triangle and h is the height of the triangle. (in this case it would be the slant height)

= 2 * 8 *22

=352 m^2

7 0

3 years ago

Read 2 more answers

Find the Range and Domain of the Binary relations

sukhopar [10]

Answer:

A = {3,5,6}

B = {1,3}

A x B = {(3,1),(3,3),(5,1),(5,3),(6,1),(6,3)}

Domain of A x B = (The x figures in ascending order)

=> {3,5,6} (Figures repeating more than once must be written only 1 time)

Range of A x B = (The y figures in ascending order)

=> {1,3}

B x A = {(1,3),(3,3),(1,5),(3,5),(1,6),(3,6)}

Domain of B x A = {1,3}

Range of A x B = {3,5,6}

8 0

3 years ago