Answer:
the third y
Step-by-step explanation:
12.5x=1.75
Solve for x:
1.75/12.5 = 0.14
1. Use the equation 12.5x=1.75
2. Now solve for x.
a. Divide 1.75/12.5
b. Now, you have .14
c. .14 is 14%
3. The answer is 14%
Answer:
25,886.01 in²
Step-by-step explanation:
The area of shaded region = Area of the outter circle (the larger circle) - area of the inner circle (the smaller circle)
Area of a circle = πr²
Radius of larger circle = PO = 93.4 in
Area of the larger circle = 3.14*93.4² = 27,391.98 in²
Radius of smaller circle = PO - RQ = 93.4 - 71.5 = 21.9
Area of smaller circle = 3.14*21.9² = 1,505.97 in²
Area of shaded region = 27,391.98 - 1,505.97 = 25,886.01 in²
The volume of a sphere is (4/3) (pi) (radius cubed).
The volume of one sphere divided by the volume of another one is
(4/3) (pi) (radius-A)³ / (4/3) (pi) (radius-B)³
Divide top and bottom by (4/3) (pi) and you have (radius-A)³ / (radius-B)³
and that's exactly the same as
( radius-A / radius-B ) cubed.
I went through all of that to show you that the ratio of the volumes of two spheres
is the cube of the ratio of their radii.
Earth radius = 6,371 km
Pluto radius = 1,161 km
Ratio of their radii = (6,371 km) / (1,161 km)
Ratio of their volumes = ( 6,371 / 1,161 ) cubed = about <u>165.2</u>
Note:
I don't like the language of the question where it asks "How many spheres...".
This seems to be asking how many solid cue balls the size of Pluto could be
packed into a shell the size of the Earth, and that's not a simple solution.
The solution I have here is simply the ratio of volumes ... how many Plutos
can fit into a hollow Earth if the Plutos are melted and poured into the shell.
That's a different question, and a lot easier than dealing with solid cue balls.
