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Neko [114]
3 years ago
10

What series of transformations map triangle △ABC onto △EDF ​ to prove that ABC≅EDF ?

Mathematics
2 answers:
Nonamiya [84]3 years ago
7 0
Hello!

The correct answer is A translation 3 units up then a reflection across the x-axis.

Translation: moving/sliding a figure
Reflection: taking a figure and flipping it over a line.
kondaur [170]3 years ago
4 0

Answer:  

translation 3 units down then a reflection across x-axis

Step-by-step explanation:

  • A translation is a kind of rigid motion . It trace a function that maps an object a particular distance.
  • A reflection is a kind of rigid motion . It is mainly a flips of a shape across the line of reflection.

In the given figure, we can see that Δ ABC is vertically 3 units away from the x axis .

So we translate  Δ ABC by 3 units down and then reflect it across x axis to get ΔDEF.

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Move 12 to the other side, making it negative
h=31-12
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Triangle ABC is transformed to triangle A′B′C′, as shown below:
Akimi4 [234]

Answer:

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3 years ago
Find values of  that satisfy the equation for 0º    360º and 0  θ  2 . Give answers in degrees and radians.
suter [353]

Answer:

\theta = 30^\circ, 330^\circ

\theta = \frac{\pi}{6}, \frac{11\pi}{6}

Step-by-step explanation:

Given [Missing from the question]

Equation:

cos\theta = \frac{\sqrt 3}{2}

Interval:

0 \le \theta \le 360

0 \le \theta \le 2\pi

Required

Determine the values of \theta

The given expression:

cos\theta = \frac{\sqrt 3}{2}

... shows that the value of \theta is positive

The cosine of an angle has positive values in the first and the fourth quadrants.

So, we have:

cos\theta = \frac{\sqrt 3}{2}

Take arccos of both sides

\theta = cos^{-1}(\frac{\sqrt 3}{2})

\theta = 30 --- In the first quadrant

In the fourth quadrant, the value is:

\theta = 360 -30

\theta = 330

So, the values of \theta in degrees are:

\theta = 30^\circ, 330^\circ

Convert to radians (Multiply both angles by \pi/180)

So, we have:

\theta = \frac{30 * \pi}{180}, \frac{330 * \pi}{180}

\theta = \frac{\pi}{6}, \frac{33 * \pi}{18}

\theta = \frac{\pi}{6}, \frac{11 * \pi}{6}

\theta = \frac{\pi}{6}, \frac{11\pi}{6}

8 0
2 years ago
Can you pls help?????????
Luden [163]

Answer:

see attached pdf

Step-by-step explanation:

see attached pdf

Download pdf
3 0
2 years ago
What is the slope of y = 2 + 5?
brilliants [131]

Answer:

Using the slope-intercept form, the slope is 0 .

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
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