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BlackZzzverrR [31]
2 years ago
10

A rectangle has coordinates (2, 6) (9, 6) (9, 10) and (2, 10) on a grid with 1 cm squares. What is the area of the shaded rectan

gle?
Mathematics
1 answer:
Valentin [98]2 years ago
7 0

Answer:

Area of Rectangle = 28 cm²

Step-by-step explanation:

Given - A rectangle has coordinates (2, 6) (9, 6) (9, 10) and (2, 10) on a grid with 1 cm squares.

To find - What is the area of the shaded rectangle?

Solution -

The graph of the rectangle is as follows :

From the diagram, e can see that

Length of Rectangle = 7 units (cm)

Breadth of Rectangle = 4 units (cm)

We know that,

Area of Rectangle = Length × Breadth

                              = 7 × 4

                              = 28 cm²

⇒Area of Rectangle = 28 cm²

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Answer:

$1.44

Step-by-step explanation:

<u>Store A:</u>

12 bottles of water for $3.36

Then

48 bottles of water for \$3.36\cdot 4=\$13.44 (48 bottles is 4 times greater than 12 bottles)

<u>Store B:</u>

24 bottles of water for $6.00

Then

48 bottles of water for \$6.00\cdot 2=\$12 (48 bottles is twice greater than 24 bottles)

<u>Difference:</u>

\$13.44-\$12=\$1.44

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2 years ago
Your electric bill has been as follows for the past six months:
kakasveta [241]

You want to find the monthly average over the past 6 months.


July: $78.56

August: $30.21

September: $81.20

October: $79.08

November: $66.18

December: $100.75


Add all of these up

(July) $78.56

(August) $30.21

(September) $81.20

(October) $79.08

(November) $66.18

(December) + $100.75

----------------------------------------------

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There are 6 months you are calculating for, therefore divide the total (combined) cost of 6 months with the total number of months (in this case, 6)


$435.88 (total cost of 6 months) ÷ 6 (months)


The average cost per month of over the past 6 months is $72.66.

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A bookkeeper bought 2,000 exercise book distributed 200 books to the student from poor economic background as donation .he sold
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Books left=2000-200=1800

ATQ

\\ \sf\longmapsto 1800x+10=0.08x

\\ \sf\longmapsto 1800x-0.08x=-10

\\ \sf\longmapsto x(1800-0.08)=-10

\\ \sf\longmapsto x(1799.92)=-10

\\ \sf\longmapsto x=|\dfrac{10}{1799.92}|

\\ \sf\longmapsto x=0.005

Now

\\ \sf\longmapsto CP=0.005(2000)=10

6 0
2 years ago
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