Answer:
.5 and .5, .75 and .25, ect
To Find :
How many gallons of a 80% antifreeze solution must be mixed with 100 gallons of 20% antifreeze to get a mixture that is 70% antifreeze.
Solution :
Let, x gallons of 80% antifreeze solution is required :
So,

Therefore, 500 gallons of 80% antifreeze solution is required.
X is equal to -11/6 or -1.8333333333..................................
Answer:
A,B, and C
Step-by-step explanation:
25%of 24 is 6, 24-6=18(new price)
A.24-(0.25×24)=24-6=18
B.(0.75)×24=18
C.(0.25×24)×3= 6×3=18
It looks like it counts up by 2 when adding. so add 4, then add 6, then add 8, then add 10, etc. to find the output you simply add 2 more than the last time you added, to find the input, you subtract 2 more than last time. hope this makes sense haha.