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qwelly [4]
2 years ago
6

Find the unknown length x in the right triangle, to the nearest tenth.

Mathematics
1 answer:
gtnhenbr [62]2 years ago
5 0

Answer:

x=46.364

Step-by-step explanation:

cos(75 degree)=12/x

x=46.364

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If f(x)=(2x^2)-1, find:<br> -f(3x-1)+2
Sergeeva-Olga [200]

Answer:

-f(3x - 1) + 2 = -18x² + 12x + 1

Step-by-step explanation:

Step 1: Find f(3x - 1)

f(3x - 1) = 2(3x - 1)² - 1

f(3x - 1) = 2(9x² - 6x + 1) - 1

f(3x - 1) = 18x² - 12x + 2 - 1

f(3x - 1) = 18x² - 12x + 1

Step 2: Plug in f(3x - 1)

-(18x² - 12x + 1) + 2

Step 3: Evaluate

-18x² + 12x - 1 + 2

-f(3x - 1) + 2 = -18x² + 12x + 1

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If sinX= 0.9, what is the value of cos X?<br><br> Round the value to the nearest thousandth.
SSSSS [86.1K]

Answer: sqrt(19)/10

Step-by-step explanation:

sinx=0.9

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Insert x for cos(x):

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Use identify cos(arcsin(x))=\sqrt{1-x^{2} }, so

\sqrt{1-(\frac{9}{10})^{2}} =\sqrt{\frac{19}{100} } =\frac{\sqrt{19}}{10}


Sorry if this is confusing.



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