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Dahasolnce [82]
3 years ago
15

12. What's

Mathematics
1 answer:
Sholpan [36]3 years ago
3 0

Answer:

C.)

Step-by-step explanation:

Denominator is the bottom part of a fraction

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What is the slope of a line perpendicular to the line whose equation is 2x+2y=28
malfutka [58]

Answer:

1

Step-by-step explanation:

1) First, place the given equation in slope-intercept form (y = mx +b format) to find its slope easier. Isolate the y:

2x + 2y = 28\\2y = -2x + 28\\y = -x+14

So, the equation of the line in slope-intercept form is y = -x + 14. When an equation is in slope-intercept form, the m, or the coefficient of the x-term, represents the slope. Thus, the slope for the given line would be -1.

2) Lines that are perpendicular have slopes that are opposite reciprocals of each other. We need to find the opposite reciprocal of -1, then.

To find the opposite reciprocal of a number, write the given number as a fraction first -- making -1 be written as   -\frac{1}{1} -- then switch the sign and flip the numerator and denominator. So, the opposite reciprocal of -1 is 1, and 1 is the slope of the perpendicular line.

3 0
3 years ago
Find the maximum power of 5 which can divide 49!
JulijaS [17]

Answer:

10

Step-by-step explanation:

8 0
3 years ago
Find the Arithmetic mean<br> between 6 and 12​
mafiozo [28]

Step-by-step explanation:

Arithmetic mean

A.M. =  \frac{6 + 12}{2}  =  \frac{18}{2}  = 9 \\

6 0
3 years ago
Read 2 more answers
35 is the sum of a number and 7
Scorpion4ik [409]

Answer:

7+28=35

Step-by-step explanation:

4 0
3 years ago
Given that x and y are positive integers, solve the equation x² - 4y² = 13​
zvonat [6]
<h3>Answer:  x = 7 and y = 3</h3>

=====================================================

Explanation:

Apply the difference of squares rule

x² - 4y² = 13

x² - (2y)² = 13

(x - 2y)(x + 2y) = 13

Since x and y are positive integers, this means x-2y and x+2y are both integers as well.

The value 13 is prime. Its only factors are 1 and 13

Since the above equation shows 13 factoring into x-2y and x+2y, then we have two cases:

  • A) x-2y = 1 and x+2y = 13
  • B) x-2y = 13 and x+2y = 1

----------------

Let's consider case A

We have this system of equations

\begin{cases}x-2y = 1\\x+2y = 13\end{cases}

Add the equations straight down

  • x+x becomes 2x
  • -2y+2y becomes 0y = 0 which goes away
  • 1+13 becomes 14

Therefore we have 2x = 14 solve to x = 7

From here, plug this into either equation to solve for y

x-2y = 1

7 - 2y = 1

-2y = 1-7

-2y = -6

y = -6/(-2)

y = 3

You should get the same result if you used x+2y = 13

----------------

Since we've found that x = 7 and y = 3, notice how case B is not possible

Example:  x-2y = 13 becomes 7-2(3) = 13 which is false.

Also, x+2y = 1 would turn into 7+2(3) = 1 which is also false.

-----------------

Let's check those x and y values in the original equation

x² - 4y² = 13

7² - 4*(3)² = 13

49 - 4(9) = 13

49 - 36 = 13

13 = 13

The answer is confirmed.

4 0
2 years ago
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