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Rom4ik [11]
3 years ago
10

4. A sequence starts with 1 then 10.

Mathematics
1 answer:
Mumz [18]3 years ago
7 0

Answer:

thank you

Step-by-step explanation:

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Josh makes a fruit salad with bananas, blueberries, and strawberries. He uses 234 pounds of bananas, 112 pounds of blueberries,
4vir4ik [10]

Answer:

234+112=346

618-346=272

Josh used 272 pounds of strawberries in his fruit salad.

Step-by-step explanation:

6 0
2 years ago
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PLZ HELP ME! THIS IS SERIOUS!!!!<br> WHAT’S 3+3?!?!?!??!?!?
k0ka [10]
Ok the answers is 6 but don’t be mad if I’m wrong
8 0
2 years ago
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The equation C = 5 9 F − 160 9 gives the relation between temperature readings in Celsius and Fahrenheit.
Pavel [41]

Step-by-step explanation:

The question is wrong. The correct equation is :

C=\frac{5}{9}F-\frac{160}{9}

We know that the equation gives the relation  between temperature readings in Celsius and Fahrenheit.

Therefore, giving that we know the value in Fahrenheit ''F'' we can find the reading in Celsius ''C''. This define a function C(F) that depends of the variable ''F''.

So for the incise (a) we answer Yes, C is a function of F.

For (b) we need to find the mathematical domain of this function. Giving that we haven't got any mathematical restriction, the mathematical domain of the function are all real numbers.

Dom (C) = ( - ∞ , + ∞)

For (c) we know that the water in liquid state and at normal atmospheric pressure exists between 0 and 100 Celsius.

Therefore the range will be

Rang (C) = (0,100)

Now, we need to find the domain for this range. We do this by equaliting and finding the value for the variable ''F'' :

For C = 0 :

0=\frac{5}{9}F-\frac{160}{9} ⇒ F=32

And for C = 100 :

100=\frac{5}{9}F-\frac{160}{9} ⇒ F=212

Therefore, the domain as relating temperatures of water in its liquid state is

Dom (C) = (32,212)

For (d) we only need to replace in the equation by F=71 and find the value of C ⇒

C=\frac{5}{9}F-\frac{160}{9} ⇒

C=(\frac{5}{9})(71)-\frac{160}{9}

C=\frac{65}{3} ≅ 21.67

C(71) = 21.67 °C

4 0
2 years ago
A scale drawing of a field is shown below. The drawing uses a scale of 1 in. = 14 ft. What is the area of the actual field?
svp [43]

Answer:

D. 4,704 ft²

Step-by-step explanation:

Giving a scale of 1 in. = 14 ft, to find the actual area of the field represented by the triangular drawing above, convert the length of the base and height to the actual lengths of the field using the scale.

Height of drawing = 8 in.

Actual height = 8*14 = 112 ft

Base of drawing = 6 in.

Actual base = 6*14 = 84 ft

Area of the field = area of ∆

Area = ½*base*height

Area = ½*84*112

Area = 4,704 ft²

3 0
2 years ago
PLS HELP MEEE !!!!!
kotykmax [81]

Answer:

5 terms

Step-by-step explanation:

x is one term

-3 is one term

2y is one term

-16 is one term

4x is one term

5 terms in total

7 0
2 years ago
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