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lys-0071 [83]
3 years ago
9

What is the measurement of MKN? Please show all work on how you got your answer

Mathematics
2 answers:
dangina [55]3 years ago
8 0

Answer:

90*

Step-by-step explanation:

Ronch [10]3 years ago
5 0

Answer:

2

Step-by-step explanation:

LK = 1

MKN = MK + KN

MK = LK

KN = LK

MK = 1

KN = 1

1 + 1 = 2

MKN = 2

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fred ha 227 dollars to spend on 6 books after buying them he had 17 dollars how much did each book cost
NemiM [27]

Answer:

$35

Step-by-step explanation:

If Fred has 227 total and ends up with 17, do 227-17 to determine how much he spent. ($210). If he bought 6 books, then divide $210 by 6.

Hence, each book was $35

7 0
3 years ago
Find four consecutive even integers whose sum is 668
lesya692 [45]

Answer:

x+ x+2+ x+4+ x+6 = 668

4x+12 = 668

4x = 668-12

4x = 658

x = 658/4

x = 164

x+2 = 164+2  

      = 166

x+4 = 164+4

       = 168

x+6 = 164+6

       = 170

Hope it helps u mate.....

5 0
3 years ago
If a function, f(x) is shifted to the left 4 unit(s), what function represents the transformation?
ElenaW [278]
I hope this is right f(x+4)
4 0
3 years ago
A random sample of 384 people in a mid-sized city (city one) revealed 112 individuals who worked at more than one job. A second
Svetlanka [38]

Answer:

99% confidence interval is:

(0.00278 < P1 - P2< 0.15921)

Step-by-step explanation:

For calculating a confidence intervale for the difference between the proportions of workers in the two cities, we calculate the following:

[(p_{1} - p_{2}) \pm z_{\alpha/2} \sqrt{\frac{p_{1}(1-p_{1})}{n_{1}} + \frac{p_{2}(1-p_{2})}{n_{2}} }

             Where  p_{1} : proportion sample of individuals who worked      

                                                     at more than one job in the city one

                           n_{1}: Number of respondents in the city one

                           p_{1} : proportion sample of individuals who worked      

                                                     at more than one job in the city two

                           n_{1}: Number of respondents in the city two

Then

α = 0.01 and α/2 = 0.005

and z_{\alpha/2} = 2.575

p_{1} = \frac{112}{384} = 0.2916

p_{2} = \frac{91}{432} = 0.2106

n_{1}= 384  and n_{2}= 432

The confidence interval is:

[(0.2916 - 0.2106) \pm 2.575 \sqrt{\frac{0.2916(1-0.2916)}{384} + \frac{0.2106(1-0.2106)}{432} }

(0.00278 < P1 - P2< 0.15921)

5 0
3 years ago
4 plates and 3 cups cost 20.90 dollars. 5 plates and 4 cups cost 26.50 dollars. Each plate costs the same amount as the other pl
shutvik [7]

Answer:

Hope this helps you understand...

3 0
3 years ago
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