Question

Solve for x in the equation x^2+4x-4=8

Answer 1

Answer:

The solutions are $x=2,\:x=-6$

Step-by-step explanation:

To solve for $x$ the equation $x^2+4x-4=8$ you must:

$\mathrm{Subtract\:}8\mathrm{\:from\:both\:sides}\\\\x^2+4x-4-8=8-8\\\\x^2+4x-12=0$

$\mathrm{Factor\:}x^2+4x-12\\\\\mathrm{Break\:the\:expression\:into\:groups}\\\\\left(x^2-2x\right)+\left(6x-12\right)\\\\x\left(x-2\right)+6\left(x-2\right)\\\\\mathrm{Factor\:out\:common\:term\:}x-2\\\\x\left(x-2\right)+6\left(x-2\right)$

Using the Principle of Zero Products.

If ab = 0, then either a = 0 or b = 0, or both a and b are 0.

$x-2=0\\x=2$

$x+6=0\\x=-6$

The solutions are $x=2,\:x=-6$.

Answer 2

X is equal to -2
Hope this helps