We will first put this data in ascending order
12,13,13,15,16,19,32
We then center in on the middle number, we first can “mark out” the highest and lowest number and repeat until we have one number left
12,13,13,15,16,19,32
13,13,15,16,19
13,15,16
The median is 15
A parabola is a quadratic function, and a quadratic can be expressed in vertex form, which is:
y=a(x-h)^2+k, where (h,k) is the vertex (absolute maximum or minimum point of the quadratic)
In this case we are given that (h,k) is (-5,80) so we have so far:
y=a(x--5)^2+80
y=a(x+5)^2+80, we are also told that it passes through the point (0,-45) so:
-45=a(0+5)^2+80
-45=25a+80 subtract 80 from both sides
-125=25a divide both sides by 25
-5=a, so now we know the complete vertex form is:
y=-5(x+5)^2+80
The x-intercepts occur when y=0 so:
0=-5(x+5)^2+80 add 5(x+5)^2 to both sides
5(x+5)^2=80 divide both sides by 5
(x+5)^2=16 take the square root of both sides
x+5=±√16 which is
x+5=±4 subtract 5 from both sides
x=-5±4 so the x-intercepts are:
x=-1 and -9
Answer:
Choice 2
Step-by-step explanation:
Answer:
x=10
Step-by-step explanation:
x-1 = 9
add 1 on both side
x-1+1=9+1
x=10
