Answer:
a.The phenotypic proportions obtained after having the genotypes are 50% marbled seeds, 25% spotted and dotted seeds since they are codominant, 25% spotted seeds.
b. Taking into account the F1 genotypes in the previous point, the expected phenotypes for the first crossing are 100% marbled seeds and for the second crossing 100% dotted seeds.
Explanation:
Let's suppose:
Marbled allele: M
Spotted allele: S
Dotted allele: D
Allele for Clear: C
a. Because both crosses were between homozygous parents, the entire F1 genotype is the same.
For the first crossing the descendants have the MS genotype, and for the second crossing the descendants have the DC genotype. It is enough to make a Punnett square to obtain the different combinations of genotypes between the crossing of MS and DC.
I, seems to be the answer, because its not a sexual reproduction, (this occurs in cells, its not sexual reproduction, you would need the egg and sperm.
Answer:
Crossing over occurs in meiosis but not in mitosis
Explanation:
Miosis is a process in which diploid cell becomes a haploid cell.which is essential for sexual reproduction In mitosis the daughter cells are identical whereas in meiosis the daughter cells are different due to crossing over.the process of crossing over does not occur in mitosis.
Answer: No
Explanation:
The electrician just cannot replace any piece of wire to fuse because the ceramic that is used in case of fuse has a wire attached in it.
This wire is of low resistance so that when there is higher voltage the wire just cannot tolerate the high voltage and wire breaks down.
Any wire just cannot be replace by the fuse because the there are some calculations which has to be made.
The wire if used should be of low resistance and more properties then only it is eligible to be replaced by fuse.
Answer is C Anaguzman is right i was wrong so i put up this so as not to confuse anyone.
