Step-by-step explanation:
1.(4,9) & (1,6)
m=y²-y¹/x²-x¹
m=6-9/1-4
m=-3/-3
m= 1
2.(5,3) & (5,-9)
m=y²-y¹/x²-x¹
m=(-9)-3/5-5
m=-12/0
3.(2,1) & (8,9)
m=y²-y¹/x²-x¹
m=9-1/8-2
m=8/6
m= 4/3
4.(14,-8) & (7,-6)
m=y²-y¹/x²-x¹
m=(-6)-(-8)/7-14
m=2/-7
m= -2/7
5.(4,-3) & (8,-3)
m=y²-y¹/x²-x¹
m=(-3)-(-3)/8-4
m=0/4
m=0
6.(-11,1) & (-2,6)
m=y²-y¹/x²-x¹
m=6-1/(-2)-(-11)
m=5/9
Answer:
8
Step-by-step explanation:
1 serving=60cal
480÷60=8
hope this helps
Answer:
hi
Step-by-step explanation:
i think it is probably 9
hope it helps
The correct question is
Which is the best approximation to a solution of the equation
e^(2x) = 2e^{x) + 3?
we have that
e^(2x) = 2e^{x) + 3-----------> e^(2x)- 2e^{x) - 3=0
the term
e^(2x)- 2e^{x)----------> (e^x)²-2e^(x)*(1)+1²-1²------> (e^x-1)²-1
then
e^(2x)- 2e^{x) - 3=0--------> (e^x-1)²-1-3=0------> (e^x-1)²=4
(e^x-1)=2--------> e^x=3
x*ln(e)=ln(3)---------> x=ln(3)
ln(3)=1.10
hence
x=1.10
the answer is x=1.10
I would assume that he's using a 90° rotation.
