Question

What is the value of y in the solution to the system of equations?

Answer 1

Keywords

system of equations, linear equation, elimination method

we have

$\frac{1}{3}x+ \frac{1}{4}y=1$

Multiply by $12$ both sides

$4x+3y=12$ -----> linear equation A

$2x-3y=-30$ -----> linear equation B

Applying the elimination method for solve the system of equations

Adds equation A and equation B

$4x+3y=12 \\2x-3y=-30\\-------- \\4x+2x=12-30 \\6x=-18 \\x=-3$

Find the value of y

$4(-3)+3y=12$

$3y=12+12$

$y=8$

therefore

the answer is the option D

$8$

Answer 2

Answer:

Option d is correct

y = 8

Step-by-step explanation:

Given the system of equations:

$\frac{1}{3}x+\frac{1}{4}y = 1$         ....[1]

$2x-3y = -30$                  ....[2]

Multiply equation [1] by 12 to both sides we have;

$4x+3y = 12$                .....[3]

Add equation [2] and [3] we have;

$6x = -18$

Divide both sides by 6 we have;

x = -3

Substitute in [2] to solve for y:

2(-3)-3y = -30

-6-3y = -30

Add 6 to both sides we have;

-3y = -24

Divide both sides by -3 we have;

y = 8

Solution we get: (-3, 8)

Therefore, the value of y in the solution to the system of equations is, 8