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Over [174]
3 years ago
12

What is the value of y in the solution to the system of equations?

Mathematics
2 answers:
Vadim26 [7]3 years ago
5 0

Keywords

system of equations, linear equation, elimination method

we have

\frac{1}{3}x+ \frac{1}{4}y=1

Multiply by 12 both sides

4x+3y=12 -----> <u>linear equation</u> A

2x-3y=-30 -----> <u>linear equation</u> B

Applying the <u>elimination method</u> for solve the <u>system of equations</u>

Adds equation A and equation B

4x+3y=12 \\2x-3y=-30\\-------- \\4x+2x=12-30 \\6x=-18 \\x=-3

Find the value of y

4(-3)+3y=12

3y=12+12

y=8

therefore

the answer is the option D

8


agasfer [191]3 years ago
5 0

Answer:

Option d is correct

y = 8

Step-by-step explanation:

Given the system of equations:

\frac{1}{3}x+\frac{1}{4}y = 1         ....[1]

2x-3y = -30                  ....[2]

Multiply equation [1] by 12 to both sides we have;

4x+3y = 12                .....[3]

Add equation [2] and [3] we have;

6x = -18

Divide both sides by 6 we have;

x = -3

Substitute in [2] to solve for y:

2(-3)-3y = -30

-6-3y = -30

Add 6 to both sides we have;

-3y = -24

Divide both sides by -3 we have;

y = 8

Solution we get: (-3, 8)

Therefore, the value of y in the solution to the system of equations is, 8

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