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kakasveta [241]
3 years ago
6

What are the two solutions of x2 – 2x – 4 = –3x + 9?

Mathematics
2 answers:
Komok [63]3 years ago
6 0
<span>x=<span><span>​2</span>​<span>​<span>−1+<span>√<span><span>​<span>53</span></span>​<span>​​</span></span></span></span></span><span>​​</span></span>,<span><span>​2</span>​<span>​<span>−1−<span>√<span><span>​<span>53</span></span>​<span>​​</span></span></span></span></span><span>​​</span>

I hope this helps. :)</span></span>
bogdanovich [222]3 years ago
6 0

the x-coordinates of the intersection points of the graphs of y = x2 – 2x – 4 and y = –3x + 9

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Answer:

b

Step-by-step explanation:

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2 years ago
Shen borrowed $8000 at a rate of 12%, compounded semiannually. Assuming he makes no payments, how much will he owe after 7 years
Alexandra [31]

Answer:

$18,087.23

Step-by-step explanation:

The future worth of the loan in 7 years compounded semiannually is computed as shown below using the future value formula adjusted for semiannual compounding:

FV=PV*(1+r/2)^n*2

FV is the worth of the loan in 7 years which is unknown

PV is the actual amount of loan which is $8,000

r is the rate of interest of 12%

n is the number of years of the loan which is 7 years

the 2 is to show that interest is computed twice a year

FV=8000*(1+12%/2)^7*2

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4 0
3 years ago
Suppose that a large mixing tank initially holds 100 gallons of water in which 50 pounds of salt have been dissolved. Another br
Serggg [28]

Answer:

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Step-by-step explanation:

The differential equation of this problem is;

dA/dt = R_in - R_out

Where;

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R_out is the rate at which salt exits

R_in = (concentration of salt in inflow) × (input rate of brine)

We are given;

Concentration of salt in inflow = 4 lb/gal

Input rate of brine = 3 gal/min

Thus;

R_in = 4 × 3 = 12 lb/min

Due to the fact that solution is pumped out at a slower rate, thus it is accumulating at the rate of (3 - 2)gal/min = 1 gal/min

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Therefore;

R_out = (concentration of salt in outflow) × (output rate of brine)

R_out = [A(t)/(100 + t)]lb/gal × 2 gal/min

R_out = 2A(t)/(100 + t) lb/min

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dA/dt = 12 - 2A(t)/(100 + t)

Since we are to use A foe A(t), thus the Differential equation is now;

dA/dt = 12 - 2A/(100 + t)

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3 years ago
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Kipish [7]

Step-by-step explanation:

Based on the given conditions,

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Cross out the common factor:1/4

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Write as a single fraction :25/4×25

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5 0
2 years ago
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Answer:

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2 years ago
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