Answer:
60 minutes for the larger hose to fill the swimming pool by itself
Step-by-step explanation:
It is given that,
Working together, it takes two different sized hoses 20 minutes to fill a small swimming pool.
takes 30 minutes for the larger hose to fill the swimming pool by itself
Let x be the efficiency to fill the swimming pool by larger hose
and y be the efficiency to fill the swimming pool by larger hose
<u>To find LCM of 20 and 30</u>
LCM (20, 30) = 60
<u>To find the efficiency </u>
Let x be the efficiency to fill the swimming pool by larger hose
and y be the efficiency to fill the swimming pool by larger hose
x = 60/30 =2
x + y = 60 /20 = 3
Therefore efficiency of y = (x + y) - x =3 - 2 = 1
so, time taken to fill the swimming pool by small hose = 60/1 = 60 minutes
Answer:
B) f(x)=13x+4 and C) f(x)=|3x| − 4
Answer:
-2/3
Step-by-step explanation:
in y=mx+b, m= the slope
and if you were graphing, you would put 2 on the y axis and use the rise over run strategy for the slope
hope this helped:)
Answer: A) x=6
Step-by-step explanation: my trick that i do with these questions are to just fill in the x's with the different choices that they give you.
so... first try out 6. fill in every x with a 6. so now, x isn't x anymore, it's 6.
(8-6)=2
9 times 2= 18
3 times 6= 18
this means that x would equal 6
if that first one doesn't work, try out the other ones. but this one works, so we know we have the right answer. i hope this helps with this problem, and i hope it helps with other problems like this too.
:)
Decimal: 25.3333, but converted properly it is
.253333....(repeating) so to the nearest thousands it would be .253