x = 10.22 in
Solution:
Width of the figure = x in
Length of the figure = (2x + 5) in
Area of the figure = 260 in²
<u>To find the value of x:</u>
<em>Area of the figure = length × width</em>
length × width = 260
(2x + 5) × x = 260

Subtract 260 from both sides of the equation.

Factor the above quadratic expression.
Quadratic equation formula:




x = 10.22, x = –12.72006
Dimension of the figure cannot be measured in negative terms.
Hence x = 10.22 in.
Answer:
total distance might be 16
Step-by-step explanation:
|y2-y1/x2-x1|, plug it the numbers, if you got a negative number, its just positive since the equation is set to absolute value
Required expression is x/9 - 7
Consider this option:
1. given: n(A;B;C)=n(-5;-4;-1) and A(-1;-5;-2)=A(x₀;y₀;z₀).
Common view of equation for a plane is Ax+By+Cz+D=0, where A,B,C,D - numbers.
2. from another side using coordinates of A and normal vector it is possible to make up the equation: A(x-x₀)+B(y-y₀)+C(z-z₀)=0 ⇒ -5(x+1)-4(y+5)-(z+2)=0; ⇒ -5x-4y-z-27=0 or 5x+4y+z+27=0.