Question

Mr. Howard is a student teacher at the local junior high. His first‐period class of 40 students averaged 96% on a recent test. His second‐period class of 20 students averaged 90% on the same test. What was the combined average for both classes?

Answer 1

Answer:

94%

Step-by-step explanation:

Mr. Howard is a student teacher at the local junior high.

• First period class of 40 students averaged = 96%
• Second period class of 20 students averaged = 90%

on same test.

Total score for first period class test = 96% of 40

                                                           = 38.4

Total score for second period class test = 90% of 20

                                                                = 18

$\text{Combined average score }=\dfrac{\text{Total score of both test}}{\text{Total number of students}}$

$\text{Combined average score }=\dfrac{38.4+18}{40+20}\times 100$

                                               $=94\%$

Hence, the combined averaged test score for both classes is 94%

Answer 2

Answer:

The combined average is 94%

Step-by-step explanation:

for first period, number of students =40

average =96%

for second period, no of students =20

average =90%

but $average = \frac{sum of scores}{no of students}$

let $S_1$ =sum of students for the first period

    $S_2$ =sum of students for the second period

for first period;

$\frac{S_{1} }{40} =96%$

$S_{1}= 96*40=3840$

for second period,

$\frac{S_{2} }{20} =90%$

$S_{1}= 90*20=1800$

therefore the combined average = $\frac{S_1+S_2}{40+20}$

that is $\frac{3840+1800}{40+20}$ $= 94%$

so combined average is 94%